Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
x = 8, y = 3
Step-by-step explanation:
Equating corresponding x and y coordinates , then
- y = - x + 5 ( multiply through by - 1 )
y = x - 5 → (1)
2x - 5y = 1 → (2)
Substitute y = x - 5 into (2)
2x - 5(x - 5) = 1 ← distribute and simplify left side
2x - 5x + 25 = 1
- 3x + 25 = 1 ( subtract 25 from both sides )
- 3x = - 24 ( divide both sides by - 3 )
x = 8
Substitute x = 8 into (1) for corresponding value of y
y = 8 - 5 = 3
Answer:
0.4t
Step-by-step explanation:
1.4t-t=0.4t
Hope this helps :)
Answer:
$93
Step-by-step explanation:
<em>It izz wat it izzzz!!!</em>
<u>Answer:</u>
The correct answer option is: 19, 13, 3, -11, -29.
<u>Step-by-step explanation:</u>
We are given the following explicit formula for an arithmetic sequence:
So to find the first five terms of this sequence, we will substitute the values of 
(num here in the given formula:
Therefore, the first five terms of the sequence defined by the explicit formula are 19, 13, 3, -11, -29.
