9514 1404 393
Answer:
Step-by-step explanation:
The total number of students (32) corresponds to the total number of ratio units (3+5 = 8), so each ratio unit represents 32/8 = 4 students.
The 3 ratio units representing boys will stand for 3×4 = 12 boys.
The 5 ratio units representing girls will stand for 5×4 = 20 girls.
There are 12 boys and 20 girls in Janice's classroom.
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<em>Additional comment</em>
I find the above solution to be the easiest.
You can also write a system of equations. Let b and g represent the numbers of boys and girls, respectively.
b/g = 3/5
b +g = 32
Multiplying the first equation by g gives an expression for b that can be substituted into the second equation:
b = (3/5)g
(3/5)g +g = 32
8/5g = 32 . . . . . . . . . . . . . . . . . collect terms
g = (5/8)(32) = 5·4 = 20 . . . . . . multiply by 5/8
b = (3/5)(20) = 3·4 = 12 . . . . . . . find b using the value of g
Answer:
If n is an integer, the function that generate the sequence 10, 12, 14, 16, ... is 
Option D is correct option
Step-by-step explanation:
We are given the arithmetic sequence:
10, 12, 14, 16, ...
If n is an integer, which of these functions generate the sequence?
We need to find the nth term for the given sequence
The nth term for arithmetic sequence will be: 
where aₙ is nth term, a₁ is first term and d is common difference
Looking at the sequence a₁ = 10 and d = 2
So, nth term will be:
So, nth term is: 
In the options below, the only correct answer is option D. so, we can write nth term as: 
So, If n is an integer, the function that generate the sequence 10, 12, 14, 16, ... is
Option D is correct option
Total possibilities would be:
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
You want 5 on at-least one, so mark 5th column & 5th raw.
There are 6 in both lines with 1 common = (5,5)
In short, Your Answer would be 11
Hope this helps!
