Answer:
4 + 60 + 300 + NaN + 70000 + 600000 + 1000000 + NaN + 900000000
Answer:
The 99% confidence interval = (126.93,157.67)
Step-by-step explanation:
The formula for Confidence Interval =
Mean ± z × Standard deviation /√n
Mean = 142. 3 mmHg
Standard deviation = 20.8 mmHg.
n = 12
Z score for 99% confidence interval = 2.56
Confidence Interval =
142.3 ± 2.56 × 20.8/√12
142.3 ± 2.56 × 6.0044427996
142.3 ± 15.371373567
Confidence Interval
= 142.3 - 15.371373567
= 126.92862643
≈ 126.93
142.3 + 15.371373567
= 157.67137357
≈ 157.67
Therefore, the 99% confidence interval = (126.93,157.67)
Some basic dimensions could be 4x1 and 3x2
Answer:
<em>The answers are for option (a) 0.2070 (b)0.3798 (c) 0.3938
</em>
Step-by-step explanation:
<em>Given:</em>
<em>Here Section 1 students = 20
</em>
<em>
Section 2 students = 30
</em>
<em>
Here there are 15 graded exam papers.
</em>
<em>
(a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070
</em>
<em>
(b) Here if x is the number of students copies of section 2 out of 15 exam papers.
</em>
<em> here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15
</em>
<em>Then,
</em>
<em>
Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798
</em>
<em>
(c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1)
</em>
<em>
so,
</em>
<em>
Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938
</em>
<em>
Note : Here the given distribution is Hyper-geometric distribution
</em>
<em>
where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>
