Answer:
a) T = 20.601 N
b) T = 9.4585 N
Step-by-step explanation:
The tension in the string if the 5.8 kg box is held in place, so that it cannot move can be obtained as follows
For m = 2.1 Kg
∑ Fy = 0
T - W = 0 ⇒ T = W = m*g
⇒ T = 2.1 Kg*9.81 m/s²
⇒ T = 20.601 N (↑)
The tension in the string once the box begins to move can be obtained as follows
For M = 5.8 Kg
∑ Fx' = M*a
where x' is the direction of the slope
then
∑ Fx' = M*a ⇒ <em>T - M*g*Sin ∅ = M*a (I)</em>
For m = 2.1 Kg
∑ Fy = m*a
⇒ T - W = m*a
⇒ <em>T - m*g = m*a (II)</em>
If we solve the system of equations that comprises <em>I</em> and <em>II</em> we will know T:
T = M*m*g*(Sin ∅ -1) / (m - M)
⇒ T = (5.8 Kg)(2.1 Kg)(9.81 m/s²)(Sin 45º - 1) / (2.1 Kg - 5.8 Kg)
⇒ T = 9.4585 N
X-intercepts are (-4,0) and (10,0)
hope this helps :)
F(x)= (x number of minutes talked)*0.35 + (monthly charge of 55)
so F(x) = 0.35x + 55
Step-by-step explanation:
1. A = lw
- l = A/w
- l = (x²+7x +12) / (x + 3) =
- (x + 4)(x + 3)/(x + 3) =
- x + 4 m
2. V = lwh
- lw = V/h
- lw = (x³ + 12x²+ 47x + 60) / (x + 3) =
- (x³+ 3x² + 9x² + 27x + 20 x + 60) /(x + 3) =
- (x + 3)(x² + 9x + 20) / (x + 3) =
- x² + 9x + 20 cm²
3. A = bh
- h = A/b
- h = (f³-8) / (f-2) =
- (f - 2)(f² + 2f + 4)/(f-2) =
- f² + 2f + 4 cm
4. A = p*c
- c = A/p
- c = (3x³- 4x² + 2x + 4) / (x²- 2x + 2) =
- (3x³ - 6x² + 6x + 2x² - 4x + 4) /(x² - 2x + 2) =
- (x² - 2x + 2) (3x + 2) / (x² - 2x + 2) =
- 3x + 2 cans
5. A = lw
- l = A/w
- l = (x² + 5x - 6)/(x + 2) =
- (x - 1)(x + 6)/(x + 2) m
Answer:
-8,0 I hope it is a right answers