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Marina86 [1]
3 years ago
6

How do you concert percent into fractions in simple form

Mathematics
1 answer:
Rasek [7]3 years ago
5 0
You have to convert the percent into a decimal before you convert it into a fraction then you simplify the fraction.
Hope this helps! :)
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Cualnes el area del rombo si sus medidas en rectangulo son 12 y 5<br>​
MrMuchimi

Answer:

34

Step-by-step explanation:

8 0
3 years ago
What is the value of x ? <br> Enter your answer in the box . ° ?
BaLLatris [955]

Answer:

307°

Step-by-step explanation:

The sum of all the angles of a hexagon is equal to 900°.

So,

112+x+120+100+128+133 = 900

593+x = 900

x = 900-593

x = 307°

So, the value of x is equal to 307°.

4 0
3 years ago
A sand box has an area of 26 square feet, and the length is 5 1/2. What is the width of the sandbox?
mylen [45]

Yes the answer is 4 8/11. Happy to help!

6 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST!!! PLZ HELPPPP Two groups of students were asked how far they lived from their school. The table shows the
-Dominant- [34]

Answer:

B

Step-by-step explanation:

mean = average. to find it, add all terms, and then divide by the number of terms.

find the mean of group a:

(1+1.5+3+3.2+2.8+1.5+1.8+2.5+2.2)/9 = 2.16

find the mean of group b:

(2+2.5+3.2+3+1.8+2.4+3+1.5+1/8)/9 = 2.1694

group b is larger.

answer = b

5 0
3 years ago
The heights of 10 year old children has a normal probability distribution with mean of 54.6 inches and standard deviation of 5.7
Fofino [41]

Answer:

a) 0.69

The probability that a randomly selected 10-year old child will be more than 51.75 inches tall

P(X>51.75 ) = 0.6915

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

<em>Given mean of the Population = 54.6 inches</em>

<em>Given standard deviation of the Population = 5.7 inches</em>

<em>Let 'X' be the random variable of normal distribution</em>

Let 'X' = 51.75 inches

Z = \frac{x-mean}{S.D} = \frac{51.75-54.6}{5.7} = -0.5

<u><em>Step(ii):</em></u>-

<em>The probability that a randomly selected 10-year old child will be more than 51.75 inches tall</em>

<em>P(X>51.75 ) = P(Z>-0.5)</em>

                  = 1 - P( Z < -0.5)

                 =   1 - (0.5 - A(-0.5))

                =    1 -0.5 + A(-0.5)

               =    0.5 + A(0.5)    (∵A(-0.5)= A(0.5)

              =     0.5 +0.1915

              =  0.6915

<u><em>Conclusion</em></u>:-

<em>The probability that a randomly selected 10-year old child will be more than 51.75 inches tall</em>

<em>P(X>51.75 ) = 0.6915</em>

5 0
3 years ago
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