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katovenus [111]
3 years ago
12

the angel of elevation from where casey is standing to the top of an 84ft tall lighthouse is 58 degrees how far is casey standin

g from the lighthouse
Mathematics
2 answers:
In-s [12.5K]3 years ago
5 0

Answer: 52.489…

Step-by-step explanation:

Angle of elevation is 58 degrees, and the opposite value is 84 feet, so you’re lookin g for adjacent. That means you’ll use tangent to solve this equation:

Tan(58)=84/x

iren [92.7K]3 years ago
3 0

Answer: Casey is standing 52.5 feet from the lighthouse.

Step-by-step explanation:

A right angle triangle is formed. The height of the lighthouse represents the opposite side of the right angle triangle. The distance, h from the lighthouse to where Casey is standing represents the adjacent side of the right angle triangle. Casey's line of sight along the angle of elevation represents the hypotenuse.

To determine h, we would apply

the tangent trigonometric ratio.

Tan θ, = opposite side/adjacent side. Therefore,

Tan 58 = 84/h

h = 84/tan 58 = 84/1.6

h = 52.5 feet

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What is the domain and range for the following function and its inverse?
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First answer choice is right.

4 0
3 years ago
If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

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Then,

1052-4\times6^{3}

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188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

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So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

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Then,

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2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

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This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

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So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

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