Answer:
0.44
Step-by-step explanation:
The table and the graph is shown in the following picture
2sin²(-2490)+tan 1410=2sin²(-330-6*360)+tan (330+3*360)=
=2sin²(-330)+tan (330)=2 sin²(30-1*360)+tan (-30)=
=2sin²(30)-tan (30)=2(1/2)²-√3/3=1/2-√3/3)=(3-2√3)/6
Answer: 2 sin²(-2490)+tan (1410)=(3-2√3)/6 (≈-0.07735...)
Answer:4
Step-by-step explanation:
H= 2*26/5+8
Answer:
222 fence posts
Step-by-step explanation:
Since the log is 20 m long, correct to the nearest metre and has to be cut into fence posts which must be 90 cm long, correct to the nearest 10 centimetres, there can be x fence posts 90 cm long.
So, we have x × 90 cm = 20 m
x × 0.9 m = 20 m
x = 20 m/0.9 m
x = 222.22
x ≅ 222 fence posts
So, the largest number of fence posts that can possibly be cut from the log is 222 fence posts.
