3 years ago

Help What is the slope of the line on the graph?

Mathematics

1 answer:

Galina-37 [17]3 years ago

6 0

Slope = (Y2-Y1) / (X2-X1)
hope that's helpful

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gregori [183]

Answer:

$y=C(x+3)^2$

Step-by-step explanation:

We are given:

$\displaystyle (x+3)y^\prime=2y$

Separation of Variables:

$\displaystyle \frac{1}{y}\frac{dy}{dx}=\frac{2}{x+3}$

So:

$\displaystyle \frac{dy}{y}=\frac{2}{x+3} \, dx$

Integrate:

$\displaystyle \int\frac{dy}{y}=\int\frac{2}{x+3}\, dx$

Integrate:

$\displaystyle \ln|y|=2\ln|x+3|+C$

Raise both sides to e:

$|y|=e^{2\ln|x+3|+C}$

Simplify:

$|y|=(e^{\ln|x+3|})^2\cdot e^C$

So:

$|y|=C|x+3|^2$

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What is the slope of the line that goes through (2, 5) and (-6, -2) ?

alexira [117]

Answer:
slope = 7/8

Explanation:
Slope of the line can be calculated using the following equation:
slope = $\frac{y2 - y1}{x2 - x1}$

The two points given are:
(2,5) representing (x1 , y1)
(-6,-2) representing (x2 , y2)

Substitute with the points in the above equation to get the slope as follows:
slope = $\frac{-2 - 5}{-6 - 2}$ = 7/8

Hope this helps :)

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W = 3A - 6
W = 33

33 = 3A - 6
33 + 6 = 3A
39 = 3A
39/3 = A
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