F~1/r²
doubling the distance r, Decreases the force by ¼
<span>When chemical change takes place, the atoms in the reactants rearrange and bond together differently to form one or more new products with different characteristics. </span>
Answer:
Explanation:
The center of mass lies on a line that joins position 4 of one start with position 4 of the other star. The shortest distance between these two points will produce the largest velocity. You are using F = m v^2/R
Small R = large force.
Large Force = increased speed.
The masses don't have any effect on the outcome: they remain constant.
The model bridge captures all the structural attributes of the real bridge, at a reduced scale.
Part a.
Note that volume is proportional to the cube of length. Therefore the actual bridge will have 100^3 = 10^6 times the mass of the model bridge.
Because the model bridge weighs 50 N, the real bridge weighs
(50 N)*10^6 = 50 MN.
Part b.
The model bridge matches the structural characteristics of the actual bridge.
Therefore the real bridge will not sag either.
Is this practically possible? How can a 100kg man fly? Hahaha
