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Alisiya [41]
4 years ago
15

A roofer drops a nail that hits the ground traveling at 26 m/s. How fast was the nail traveling 1 second before it hits the grou

nd?
Physics
1 answer:
ELEN [110]4 years ago
5 0
This problem can be solved using a kinematic equation. For this case, the following equation is useful:

v_final = v_initial + at

where,
v_final = final velocity of the nail
v_initial = initial velocity of the nail
a = acceleration due to gravity = 9.8 m/s^2
t = time 

First, we determine the time it takes for the nail to hit the ground. We know that the initial velocity is 0 m/s since the nail was only dropped. It has a final velocity of 26 m/s. We substitute these values to the equation and solve for t:

26 = 0 + 9.8*t
t = 26/9.8 = 2.6531 s

The problem asks the velocity of the nail at t = 1 second. We then subtract 1 second from the total time 2.6531 with v_final as unknown.

v_final = 0 + 9.8(2.6531-1) = 16.2004 m/s.

Thus, the nail was traveling at a speed of 16. 2004 m/s, 1 second before it hit the ground. 

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PHYSICS
quester [9]

Answer:

c) 8.3 x 10^24 molecules

Explanation:

First of all, we convert the volume of the glass of water from mL to cm^3:

V=250 mL = 250 cm^3

The relationship between mass and volume is:

d=\frac{M}{V}

where

d=1.00 g/cm^3 is the density of water

M is the total mass of the glass of water

V=250 cm^3 is the volume of the water in the glass

Solving for M,

M=dV=(1.00)(250)=250 g = 0.250 kg

Now we know that the mass of a single molecule of water is

m=3.0\cdot 10^{-26}kg

The total mass of the water in the glass can be written as

M=Nm

where

N is the number of molecules in the glass of water

Solving for N, we find:

N=\frac{M}{m}=\frac{0.250}{3.0\cdot 10^{-26}}=8.3\cdot 10^{24}

7 0
3 years ago
Can you answer fast plz
tatyana61 [14]

Answer:

wavelength frequency

energy

energy

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Explanation:

7 0
3 years ago
The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 2.0 rev/s in 10.0 s. At th
Arte-miy333 [17]

Answer:

22 revolutions

Explanation:

2 rev/s = 2*(2π rad/rev) = 12.57 rad/s

The angular acceleration when it starting

\alpha_a = \frac{\Delta \omega}{\Delta t} = \frac{12.57}{10} = 1.257 rad/s^2

The angular acceleration when it stopping:

\alpha_o = \frac{\Delta \omega}{\Delta t} = \frac{-12.57}{12} = -1.05 rad/s^2

The angular distance it covers when starting from rest:

\omega^2 - 0^2 = 2\alpha_a\theta_a

\theta_a = \frac{\omega^2}{2\alpha_a} = \frac{12.57^2}{2*1.257} = 62.8 rad

The angular distance it covers when coming to complete stop:

0 - \omega^2 = 2\alpha_o\theta_o

\theta_o = \frac{-\omega^2}{2\alpha_o} = \frac{-12.57^2}{2*(-1.05)} = 75.4 rad

So the total angular distance it covers within 22 s is 62.8 + 75.4 = 138.23 rad or 138.23 / (2π) = 22 revolutions

6 0
3 years ago
Which statements describe velocity and acceleration? Check all that apply.
Tom [10]

Velocity is defined by rate of change in the position

which we can also write as

v = \frac{ds}{dt}

while acceleration is defined as rate of change in velocity

a = \frac{dv}{dt}

so acceleration and velocity both are rate of change in position and rate of change in velocity with respect to time respectively

out of all above statement the correct answer must be

<u>Acceleration equals change in velocity divided by time. </u>

4 0
3 years ago
Read 2 more answers
Evidence that the cosmic background radiation really is the remnant of a Big Bang comes from predicting characteristics of remna
mario62 [17]

Answer:

B) The cosmic background radiation is expected to contain spectral lines of hydrogen and helium, and it does.

Explanation:

3 0
3 years ago
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