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charle [14.2K]
3 years ago
7

How much work is done by a 120N force applied to a box that moves 5m?

Physics
1 answer:
Vsevolod [243]3 years ago
4 0

Answer:

600 Joules

Explanation:

Using the formula F*d*cosФ. Assuming the Ф is parallel to the motion. The work done is 600 Joules.

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DerKrebs [107]

Melting ice would damage this polar bears habitat meaning the polar bear may decrease


5 0
3 years ago
Which of the following is a TRUE statement?
pshichka [43]

Answer:

e. All of these statements are false.

Explanation:

As we know that heat transfer take place from high temperature to low temperature.

It is possible to convert all work into heat but it is not possible to convert all heat in to work some heat will be reject to the surrounding.

The first law of thermodynamics is the energy conservation law.

Second law of thermodynamics  states that it is impossible to construct a device which convert all energy into work without rejecting the heat to the surrounding.

By using heat pump ,heat can transfer from cooler body to the hotter body.

Therefore all the answer is False.

5 0
3 years ago
What occurs when an unstable atomic nucleus changes into other nuclei by emitting particles and energy
Klio2033 [76]
I'm not too sure but I think it's nuclear decay
6 0
3 years ago
As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t, and the vertical length
ololo11 [35]

Answer:

Explanation:

4 0
3 years ago
He starter motor of a car engine draws a current of 170 AA from the battery. The copper wire to the motor is 6.00 mmmm in diamet
sweet-ann [11.9K]

Answer:

129.2 C

0.33758239177 mm

Explanation:

n = Number density = 8.46\times 10^{28}\ electrons/m^3

i = Current = 170 A

t = Time taken = 0.76 s

d = Diameter = 6 mm

Charge is given by

q=it\\\Rightarrow q=170\times 0.76\\\Rightarrow q=129.2\ C

The charge passing throught the motor is 129.2 C

Current density

J=\dfrac{i}{A}\\\Rightarrow J=\dfrac{170}{\dfrac{\pi}{4}\times (6\times 10^{-3})^2}\\\Rightarrow J=6012520.07236\ A/m^2

Drift velocity is given by

v_d=\dfrac{J}{ne}\\\Rightarrow v_d=\dfrac{6012520.07236}{8.46\times 10^{28}\times 1.6\times 10^{-19}}\\\Rightarrow v_d=0.000444187357592\ m/s

Distance traveled

s=v_dt\\\Rightarrow s=0.000444187357592\times 0.76\\\Rightarrow s=0.00033758239177\ m=0.33758239177\ mm

The electron traveled 0.33758239177 mm

8 0
3 years ago
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