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charle [14.2K]
3 years ago
7

How much work is done by a 120N force applied to a box that moves 5m?

Physics
1 answer:
Vsevolod [243]3 years ago
4 0

Answer:

600 Joules

Explanation:

Using the formula F*d*cosФ. Assuming the Ф is parallel to the motion. The work done is 600 Joules.

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Fofino [41]

Answer:

Wave Variables

In the chapter on motion in two dimensions, we defined the following variables to describe harmonic motion:

Amplitude—maximum displacement from the equilibrium position of an object oscillating around such equilibrium position

Frequency—number of events per unit of time

Period—time it takes to complete one oscillation

For waves, these variables have the same basic meaning. However, it is helpful to word the definitions in a more specific way that applies directly to waves:

].

Explanation:

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3 years ago
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How do scientists determine motion of objects in the universe??
Katen [24]
Usually, Scientists use "Parallax Method" in order to determine the different positions of an object

Hope this helps!
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3 years ago
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PLZZZZZZZZ HELP FOR 25 POINTSS !!!!!!!
trasher [3.6K]
The answer is B, luminous. Because of that fact that absorbing is taking light and Illuminated means having light because of a different light source. Luminous means bright and having lots of light. Hope this helps :)
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4 years ago
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if a ball is released from a height 80cm how long would it take the ball to reach the ground when g= 10m per seconds​
VLD [36.1K]

Answer:

The ball took 0.4 seconds

Explanation:

» From the second newton's equation of motion.

{ \boxed{ \tt{s = ut +  \frac{1}{2} {gt}^{2}  }}}

  • s is displacement, s = 80cm, s = 0.8 meters
  • u is initial velocity, u = 0 [ from rest ]
  • g is 10 m/s²

{ \tt{0.8 = (0 \times t) + ( \frac{1}{2}  \times 10 \times  {t}^{2} )}} \\  \\ { \tt{0.8 = 5 {t}^{2} }} \\ { \tt{ {t}^{2} = 0.16 }} \\ { \tt{t =  \sqrt{0.16} }} \\  \\ { \underline{ \underline{ \tt{ \: time = 0.4 \: seconds \:  \: }}}}

4 0
3 years ago
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In the absence of air resistance, at what other angle will a thrown ball go the same distance as one thrown at an angle of 75 de
snow_tiger [21]

As we know that range of the projectile motion is given by

R = \frac{v^2 sin(2\theta)}{g}

here we know that range will be same for two different angles

so here we can say the two angle must be complementary angles

so the two angles must be

\theta, 90 - \theta

so it is given that one of the projection angle is 75 degree

so other angle for same range must be 90 - 75 = 15 degree

so other projection angle must be 15 degree

5 0
3 years ago
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