It's not so much a "contradiction" as an approximation. Newton's law of gravitation is an inverse square law whose range is large. It keeps people on the ground, and it keeps satellites in orbit and that's some thousands of km. The force on someone on the ground - their weight - is probably a lot larger than the centripetal force keeping a satellite in orbit (though I've not actually done a calculation to totally verify this). The distance a falling body - a coin, say - travels is very small, and over such a small distance gravity is assumed/approximated to be constant.
Answer:
the thermistor temperature = 
Explanation:
Given that:
A thermistor is placed in a 100 °C environment and its resistance measured as 20,000 Ω.
i.e Temperature
Resistance of the thermistor
20,000 ohms
Material constant
= 3650
Resistance of the thermistor
= 500 ohms
Using the equation :


Taking log of both sides





Replacing our values into the above equation :






Thus, the thermistor temperature = 
الجواب هو الأول الجواب هو الأول
Answer:
44.72m/s
Explanation:
use th formula:vf²=vi²at
and then substitute the values
remember the units
Experiments and investigations must be B. Repeatable.