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Zolol [24]
4 years ago
14

Inequalities and linear programming

Mathematics
1 answer:
laila [671]4 years ago
7 0
Go on the website there is all the answers
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3 years ago
Please help it's do today!!
astraxan [27]

Answer:

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Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
Need help,kinda confused on this. Use the rectangle to find the lengths of the following sides if AC=26 and BC=10. Added picture
yarga [219]

1) Diagonals of a rectangle bisect each other, so AW=13.

2) Since diagonals of a rectangle are congruent, AC=BD. Then, since diagonals of a rectangle bisect each other, DW=13.

3) Diagonals of a rectangle are congruent, so BD=26.

4) Opposite sides of a rectangle are congruent, so AD=10.

5) Using the Pythagorean theorem, BA=24.

7 0
2 years ago
Which of the following is true regarding the angle shown?
Marat540 [252]

Answer:

C

Step-by-step explanation:

We know that A is not true because the angle is formed by rays, not line segments. We know this because the ends of the lines are arrowheads, which indicates that they are rays. You might be saying that A is true because BA and BC form the angle but actually, even if you removed points A and C, you would still have the angle. B is not correct because according to the diagram, the vertex is point B, not point A. The vertex of an angle is the common endpoint of the two rays that form the angle, therefore it would be point B. D is not correct because angles can have multiple names, the letters do not have to be in alphabetical order. Therefore, C is correct.

5 0
3 years ago
LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6
USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: \mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

The coordinates are given as:

\mathbf{(x,y) = (-60,0)\ (60,0)}

The center of the hyperbola  is  

\mathbf{(h,k) = (0,0)}

The distance from the center to the focal points is given as:

\mathbf{c = 60}

Square both sides

\mathbf{c^2 = 3600}

The distance from the receiver to the transmitters  is given as:

\mathbf{2a = 100}

Divide both sides by 2

\mathbf{a = 50}

Square both sides

\mathbf{a^2 = 2500}

We have:

\mathbf{b^2 = c^2 - a^2}

This gives

\mathbf{b^2 = 3600 - 2500}

\mathbf{b^2 = 1100}  

The equation of an hyperbola is:

\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}

So, we have:

\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}

\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

Hence, the equation of the hyperbola is: \mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

Read more about hyperbolas at:

brainly.com/question/15697124

7 0
3 years ago
Read 2 more answers
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