The types of realistic fiction:<u> are </u><u>historical </u><u>and </u><u>contemporary </u><u>fiction.</u>
Practical fiction creates imaginary characters and conditions that depict our world and society. It focuses on themes of growing up and confronting non-public and social problems. This genre portrays characters coming to apprehend themselves and others.
Realistic Fiction is divided into two elements: ancient and modern-day fiction. ancient fiction takes place in a time far-flung enough to be taken into consideration records, as opposed to contemporary fiction which takes vicinity these days or within the recent beyond. sensible fiction is a style of testimonies in which the events are made up, but they may easily occur in actual existence. those styles of stories take place in acquainted, ordinary settings and have normal characters.
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Answer:
Negative sign shows that velocity of the car is decreases at a constant rate
Explanation:
We have given velocity of the car is decreases from 32 m /sec to 24 m/sec in 4 second
So initial velocity of the car u = 32 m /sec
And finally car reaches to a velocity of 24 m/sec
Time taken to change in velocity = 4 sec
So final velocity v = 24 m/sec
From first equation of motion v = u+at
So 
Negative sign shows that velocity of the car is decreases at a constant rate
Answer:
We live in a very adaptable environment. If we cannot adapt to the environment, we will not be able to survive.
Explanation:
Answer:
Explanation:
Part A) Using
light intensity I= P/A
A= Area= π (Radius)^2= π((0.67*10^-6m)/(2))^2= 1.12*10^-13 m^2
Radius= Diameter/2
P= power= 10*10^-3=0.01 W
light intensity I= 0.01/(1.12*10^-13)= 9*10^10 W/m^2
Part B) Using
I=c*ε*E^2/2
rearrange to solve for E= 
((I*2)/(c*ε))
c is the speed of light which is 3*10^8 m/s^2
ε=permittivity of free space or dielectric constant= 8.85* 10^-12 F⋅m−1
I= the already solved light intensity= 8.85*10^10 W/m^2
amplitude of the electric field E= (9*10^10 W/m^2)*(2) / (3*10^8 m/s^2)*(8.85* 10^-12 F⋅m−1)
---> E= (1.8*10^11) / (2.66*10^-3) = (6.8*10^13) = 8.25*10^6 V/m
A force of 660 n stretches a certain spring a distance of 0.300 m. what is the potential energy of the spring when a 70.0 kg mass hangs vertically from it?
