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Serggg [28]
3 years ago
12

Question 3

Physics
1 answer:
bogdanovich [222]3 years ago
7 0

The object that is best used to study the transformation between kinetic and potential energy is the clock because it has a pendulum.

A pendulum can be used to study the conversion of kinetic energy to potential energy. As the pendulum swings from side to side energy is converted from potential energy to kinetic energy and back to potential energy.

The potential energy is minimum and the kinetic energy is maximum at the middle of the pendulum. At both ends of the pendulum, the potential energy of the system is maximum.

Learn more: brainly.com/question/5624100

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Studentka2010 [4]
<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Speed = distance / time

Substitute in your values:

Speed = 720 / 8

Speed = 90

They traveled 90 miles per hour

<h3><u>✽</u></h3>

➶ Hope This Helps You!

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➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

8 0
3 years ago
Read 2 more answers
A projectile is launched with a velocity of 25 m/s at an angle of 20 degrees with respect to the horizontal. What is its initial
irina [24]

Answer:

b. 23.49 m/s

d. 8.55 m/s

d. .87 s

a. 40.8 m

Explanation:

The initial along the x-axis is given by the following formula:

V_{ox} = V_{o}Cos\theta\\\\V_{ox} = (25\ m/s)(Cos\ 20^{o})\\\\V_{ox} = 23.49\ m/s

Hence, the correct option is:

<u>b. 23.49 m/s</u>

The initial along the x-axis is given by the following formula:

V_{oy} = V_{o}Sin\theta\\V_{oy} = (25\ m/s)(Sin\ 20^{o})\\V_{oy} = 8.55\ m/s

Hence, the correct option is:

<u>d. 8.55 m/s</u>

Now, for the time to reach maximum height:

t = \frac{V_{o}Sin\theta}{g}\\\\t = \frac{(25\ m/s)Sin\ 20^{o}}{9.8\ m/s^{2}}\\\\t = 0.87\ s

Hence, the correct option is:

<u>d. .87 s</u>

<u></u>

For the range of projectile:

R = \frac{V_{o}^{2}\ Sin\ 2\theta}{g}\\\\R = \frac{(25\ m/s)^{2}(Sin\ 40^{o})}{9.8\ m/s^{2}}\\\\R =  40.9\ m

Hence, the closest option is:

<u>a. 40.8 m</u>

5 0
3 years ago
Which term describes the object that revolves around a central body?
Feliz [49]

Answer:

d satellite i think

Explanation:

i eliminated all the other answers, when i notice that Orbit, Period, and Rotation are not Bodies.

8 0
4 years ago
Read 2 more answers
Consider the acceleration of an object that is undergoing simple harmonic motion. Is this acceleration zero or nonzero?
GaryK [48]

Answer:

Non-zero

Explanation:

For a simple harmonic motion, the restoring force is given by

F = -kx (1)

where

k is the spring constant

x is the displacement of the system with respect to the equilibrium position

According to Newton's second law, the acceleration of the system is given by

a = F/m (2)

where

m is the mass of the system

So if we substitute (1) into (2) we find

a = -kx/m

so the acceleration is directly proportional to the displacement. Since the value of the displacement  in a simple harmonic motion constantly changes, the acceleration changes as well, so it is non-zero (apart from the instant where the displacement is zero, x = 0, when the acceleration is also zero)

8 0
3 years ago
A certain copper wire has a resistance of 13.0 Ω . At some point along its length the wire was cut so that the resistance of one
alekssr [168]

Answer with Explanation:

Let r be the resistance of short piece of copper wire.

Resistance of copper wire=R=13\Omega

Resistance is directly proportional to length.

If a wire has greater resistance then,the wire will be greater in length.

Therefore,resistance of long piece of wire=7r

Total resistance of copper  wire=Sum of resistance of two piece of wires

r+7r=13

8r=13

r=\frac{13}{8}ohm

Resistance of long piece of wire=7\times\frac{13}{8}=\frac{91}{8}\Omega

Resistance of short piece of wire =\frac{13}{8}\Omega

Resistivity of wire and cross section area of wire remains same .

Let L be the total  length  of wire and L' be the length of short  piece of wire.

We know that

R=\frac{\rho L}{A}=\frac{\rho}{A}L=KL

\frac{R}{L}=K

Where K=\frac{\rho}{A}=Constant

Using the formula

\frac{13}{L}=\frac{\frac{13}{8}}{L'}

\frac{L'}{L}=\frac{13}{8}\times \frac{1}{13}=\frac{1}{8}

L'=\frac{L}{8}

Length of short piece of wire=L'=\frac{L}{8}

Length of long piece of  wire=L-L'=L-\frac{L}{8}=\frac{8L-L}{8}=\frac{7}{8}L

% of length of short piece of   wire=\frac{\frac{L}{8}}{L}\times 100=12.5%%

The resistance of the short piece=\frac{13}{8}\Omega

The resistance of the long piece=\frac{91}{8}\Omega

8 0
4 years ago
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