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seropon [69]
3 years ago
7

Are plants carnivoresTure or False​

Physics
1 answer:
monitta3 years ago
3 0

Answer:

False they are producers and they don' eat anything only produce and provide

Explanation:

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What is an example of an organism that reproduces
RideAnS [48]
Sea anemones; Coral; Starfish; Some non-flowering plants. Strawberry; Onion; Potato. Mushrooms are an example<span> of asexually </span>reproducing organisms<span>.

hoped i helped my fellow brainily user</span>
4 0
4 years ago
A car accelerates from 10.0 m/s to 30.0 m/s at a rate of 3.00 m/s2. how far does the car travel while accelerating?
Snezhnost [94]
Answer is in attachment.

3 0
3 years ago
What does the letter I represent?
irina [24]
The letter i is used to signify that a number is an imaginary number. It stand for the square root of negative one.
6 0
2 years ago
A small object with momentum 7.0 kg∙m/s approaches head-on a large object at rest. The small object bounces straight back with a
EastWind [94]

Answer:

The magnitude of the large object's momentum change is 3 kilogram-meters per second.

Explanation:

Under the assumption that no external forces are exerted on both the small object and the big object, whose situation is described by the Principle of Momentum Conservation:

p_{S,1}+p_{B,1} = p_{S,2}+p_{B,2} (1)

Where:

p_{S,1}, p_{S,2} - Initial and final momemtums of the small object, measured in kilogram-meters per second.

p_{B,1}, p_{B,2} - Initial and final momentums of the big object, measured in kilogram-meters per second.

If we know that p_{S,1} = 7\,\frac{kg\cdot m}{s}, p_{B,1} = 0\,\frac{kg\cdot m}{s} and p_{S, 2} = 4\,\frac{kg\cdot m}{s}, then the final momentum of the big object is:

7\,\frac{kg\cdot m}{s} + 0\,\frac{kg\cdot m}{s} = 4\,\frac{kg\cdot m}{s}+p_{B,2}

p_{B,2} = 3\,\frac{kg\cdot m}{s}

The magnitude of the large object's momentum change is:

p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}-0\,\frac{kg\cdot m}{s}

p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}

The magnitude of the large object's momentum change is 3 kilogram-meters per second.

4 0
3 years ago
c. A car was running with a velocity of 20m/s. what will be its velocity after 30s if it's acceleration is 5m/s2​
weqwewe [10]

\large \mathfrak{Solution : }

let's use first equation of motion to solve this ;

  • \boxed{ \boxed{ v = u + at}}

  • v = 20 + (5 \times 30)

  • v = 20 + 150

  • v = 170 \:  \: m/s

Velocity after 30 seconds = 170 m/s

4 0
3 years ago
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