Answer:
62.64 RPM.
Explanation:
Given that
m= 4.6 g
r= 19 cm
μs = 0.820
μk = 0.440.
The angular speed of the turntable = ω rad/s
Condition just before the slipping starts
The maximum value of the static friction force =Centripetal force
![\mu_s\ m g=m\ \omega^2\ r\\ \omega^2=\dfrac{\mu_s\ m g}{m r}\\ \omega=\sqrt{\dfrac{\mu_s\ g}{ r}}\\ \omega=\sqrt{\dfrac{0.82\times 10}{ 0.19}}\ rad/s\\\omega= 6.56\ rad/s](https://tex.z-dn.net/?f=%5Cmu_s%5C%20m%20g%3Dm%5C%20%5Comega%5E2%5C%20r%5C%5C%20%5Comega%5E2%3D%5Cdfrac%7B%5Cmu_s%5C%20m%20g%7D%7Bm%20r%7D%5C%5C%20%5Comega%3D%5Csqrt%7B%5Cdfrac%7B%5Cmu_s%5C%20%20g%7D%7B%20r%7D%7D%5C%5C%20%5Comega%3D%5Csqrt%7B%5Cdfrac%7B0.82%5Ctimes%2010%7D%7B%200.19%7D%7D%5C%20rad%2Fs%5C%5C%5Comega%3D%096.56%5C%20rad%2Fs)
![\omega=\dfrac{2\pi N}{60}\\N=\dfrac{60\times \omega}{2\pi }\\N=\dfrac{60\times 6.56}{2\pi }\ RPM\\N=62.64\ RPM](https://tex.z-dn.net/?f=%5Comega%3D%5Cdfrac%7B2%5Cpi%20N%7D%7B60%7D%5C%5CN%3D%5Cdfrac%7B60%5Ctimes%20%5Comega%7D%7B2%5Cpi%20%7D%5C%5CN%3D%5Cdfrac%7B60%5Ctimes%206.56%7D%7B2%5Cpi%20%7D%5C%20RPM%5C%5CN%3D62.64%5C%20RPM)
Therefore the speed in RPM will be 62.64 RPM.
B.) Carbon Dioxide because the carbon is surrounded by oxygen
Green is reflected off of most plant leaves.