Answer:
Assuming that the figure is a rectangle:
x=12
angle GJH=22 degrees
Step-by-step explanation:
angle GHJ=angle IJH
5x+8=7x-16
simplify
2x=24
x=12
angle IJH=7x-16
substituting for x
IJH=7(12)-16=84-16=68 degrees
angle GJH=90-IJH
angle GJH=22 degrees
First you make 15 a fraction by putting it over 1.
Then you make 6 2/3 a mixed fraction.
To do this, you multiply 6 with 3 and add 2 to it. Then you put the number over 3.
We get
6 X 3 = 18
18 +2 = 20
20/3
Now, we divide 15/1 with 20/3.
When we divide it, we actually cross multiply it. Basically, we flip the fraction and multiply it.
So we get 15/1 X 3/20 =

.
We get 45/20 which can be simplified to
9/5 which can be simplified to
2 1/4.
So the answer is
9/4 or
2 1/4.
Volume of a rectangular prism(the baseball card case) can be defined as follows: V = lwh
V = lwh
V = 12(6.5)(1.25)
V = 97.5 cm³
33% times 90 would be $29.7
Answer:
The probability is 
Step-by-step explanation:
We can divide the amount of favourable cases by the total amount of cases.
The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8,
For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function
with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.
Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.
We can conclude that the probability for 8 rooks not being able to capture themselves is
