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Evgesh-ka [11]
3 years ago
11

Use any method to multiply (3a + 2b – c)(a – b + 2c).

Mathematics
2 answers:
umka21 [38]3 years ago
4 0

Answer:

A)

3a2 – 2b2 – 2c2 – ab + 5ac + 5bc

(3a + 2b - c)(a - b + 2c) \\  = (3 {a}^{2}  - 3ab + 6ac + 2ab - 2 {b}^{2}  + 6bc - ac + bc - 2 {c}^{2} ) \\  = 3 {a}^{2}  - ab + 5ac - 2 {b}^{2}  + 5bc -  {2c}^{2}  \\  = 3 {a}^{2}  - 2 {b}^{2}  -  {2c}^{2}  - ab + 5ac + 5bc

guajiro [1.7K]3 years ago
3 0

Answer:

option a is correct

Step-by-step explanation:

(3a + 2b - c)(a - b + 2c)

3a(a- b + 2c) +2b(a - b + 2c) - c(a - b + 2c)

multiply the brackets

3a^2 - 3ab + 6ac + 2ab - 2b^2 + 4bc - ac + bc - 2c^2

combine like terms

3a^2 - ab + 5ac - 2b^2 + 5bc - 2c^2

3a^2 - 2b^2 - 2c^2 - ab + 5ac + 5bc

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