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ryzh [129]
3 years ago
8

Please simplify.

Mathematics
2 answers:
marshall27 [118]3 years ago
8 0
It’s A. Your welcome
vladimir2022 [97]3 years ago
7 0

Answer:

\large\boxed{A.\ y^3}

Step-by-step explanation:

\text{Use}\ \dfrac{a^m}{a^n}=a^{m-n}\\\\\dfrac{y^{10}}{y^7}=y^{10-7}=y^3

\text{Other method:}

\text{We know:}\ a^n=\underbrace{a\cdot a\cdot a\cdot...\cdot a}_{n}\\\\y^{10}=\underbrace{y\cdot y\cdot y\cdot y\cdot y\cdot y\cdot y\cdot y\cdot y\cdot y}_{10}\\\\y^7=\underbrace{y\cdot y\cdot y\cdot y\cdot y\cdot y\cdot y}_7}

\dfrac{y^{10}}{y^7}=\dfrac{y\!\!\!\!\diagup\cdot y\!\!\!\!\diagup\cdot y\!\!\!\!\diagup\cdot y\!\!\!\!\diagup\cdot y\!\!\!\!\diagup\cdot y\!\!\!\!\diagup\cdot y\!\!\!\!\diagup\cdot y\cdot y\cdot y}{y\!\!\!\!\diagup\cdot y\!\!\!\!\diagup\cdot y\!\!\!\!\diagup\cdot y\!\!\!\!\diagup\cdot y\!\!\!\!\diagup\cdot y\!\!\!\!\diagup\cdot y\!\!\!\!\diagup}=y\cdot y\cdot y=y^3

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Ivahew [28]

Answer:

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What is the congruence theorem used to prove that the two triangles are congruent?
natka813 [3]

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2 years ago
Include work pleaseeeee
Angelina_Jolie [31]
Okay so to represent juice we are going to use X, and to represent water we are going to use Y.

We also know that the first two starting equations are:

6x + y = 135

4x + 2y = 110

We can re-arrange the first equation so that it equals y (for now), so it is going to end up looking like this:

y = -6x +135

Now you can take that equation and plug into either one of the starting two equations.  I chose the second equation.  We just substitute what y equals in for y in the equation, so we have:

4x + 2(135 - 6x) =  110

Now solve

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Subtract 270 from both sides

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Now divide by -8 on both sides

x = 20

We can now confirm that juice costs $20

Now lets plug that into the equation where we solved for y, to get the actual value of y.

y = 135 - 6(20)

y = 135 - 120

y = 15

The price of water costs $15

From this we can conclude that the cost of juice is $20 and the price of water is $15

5 0
3 years ago
The grades on the last history exam had a mean of 75%. Assume the population of grades on history exams is known to be normally
RUDIKE [14]
34% . <span>Since going from 75% to 82% is simply the right portion of that middle, the answer is half of 68%, or 34%.</span>
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(3/5 - 1/2) divided by 1/2 + 1.6 x (0.3 + 0.42)
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3 years ago
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