Answer:
3
Step-by-step explanation:
15 men would be left
5 women would be left
Here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
;)
Answer:
I think the figure of N and E of 48in is 2304. The figure of I and E and N and A of 32in is 1024. The figure of L and I and L and A is 144.
Step-by-step explanation:
To find the area, you have to multiply of each side in each figure. For example, Figure A and B and C and D of 16in is 16 × 16 which is 256.
A = Area
a = Side
A = 2304, A = a^2 = 48^2 = 2304.
A = 1024, A = a^2 = 32^2 = 1024.
A = 144, A = a^2 = 12^2 = 144.
I hope this answers your question!
Using pythagorean identities,tan(sin^-1(-5/13))= tan(arcsin(-5/13))
Let A = arcsin(-5/13) = -arcsin(5/13)
Thus, sin A = -5/13 and cos A = sqrt(1 - (5/13)^2) = 12/13.= tan(A)= sin(A) / cos(A)= -5/13 / (12/13)= -5/12
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