Answer:
29 and -18
Step-by-step explanation:
f(x)= -3x+12
f(-9)= -3(-9)+2
f(-9)= 27+2
f(-9)= 29
g(x)= x2
g(-9)= -9(2)
g(-9)= -18
First, you would have to divide 7000 by 205. This gives you 34 & a remainder. The owner can't pack parts of a crate so yes he does because he only has 34 full crates to ship. Leaving him with 2 extra crates left.
Answer:
a) If c=3662 then q=228 and r=14.
b) If c=-3662, then q=-229 and r=2
Step-by-step explanation:
a) Observe that 229*16=3664, since r must be in the interval [0,16), then 229 doesn't work, but 228*16=3648 and 3662-3648=14.
Then 3662=228*16+14.
b) Observe that -228*16=-3648 and -3648-14=-3662, but r= must be positive. Then -228 doesn't work.
But observe that -229*16=-3664 and -3664+2=-3662. So -3662=-229*16+2
(i) The percentage of students who got high scores in both the subjects English and Mathematics is 46%.
(ii) The total number of students who got high scores either in Mathematics or in English if 300 students had attended the exam exists 138.
<h3>What is probability?</h3>
The probability exists in the analysis of the possibilities of happening of an outcome, which exists acquired by the ratio between favorable cases and possible cases.
The number of students who got high scores in Mathematics was 75%.
The number of students who got high scores in English was 65%.
(i) The percentage of students who got high scores in both the subjects
100% - 6% = 94%
(75% + 65%) - 94%
= 140% - 94%
= 46%
Therefore, the percentage of students who got high scores in both the subjects English and Mathematics is 46%.
(ii) The total number of students who got high scores either in Mathematics or in English if 300 students had attended the exam
= 300
46%
= 300
(46 / 100)
= 300
0.46
= 138.
Therefore, the total number of students who got high scores either in Mathematics or in English if 300 students had attended the exam exists 138.
To learn more about probability refer to:
brainly.com/question/13604758
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Answer:
30.8936
Step-by-step explanation:
Pressure guage reading is 8% lower than tbe actual pressure.
Therefore, for a tyre with guage pressure, 33.58 ;
The actual pressure of tyre would be :
Guage pressure - 8% of guage pressure
33.58 - (0.08 * 33.58)
33.58 - 2.6864
= 30.8936
Actual pressure = 30.8936