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mojhsa [17]
3 years ago
15

How i can find 7 times 754 using two different methods

Mathematics
2 answers:
g100num [7]3 years ago
4 0
You can add 754 7 times, or just multiply regularly.
Ierofanga [76]3 years ago
3 0
Or you could do 7x742 and 742x7
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What is the sum of the arithmetic sequence 3, 9, 15…, If there are 34 terms?
snow_tiger [21]

Answer:

first we find the common difference.....do this by subtracting the first term from the second term. (9 - 3 = 6)...so basically, ur adding 6 to every number to find the next number.

we will be using 2 formulas....first, we need to find the 34th term (because we need this term for the sum formula)

an = a1 + (n-1) * d

n = the term we want to find = 34

a1 = first term = 3

d = common difference = 6

now we sub

a34 = 3 + (34-1) * 6

a34 = 3 + (33 * 6)

a34 = 3 + 198

a34 = 201

now we use the sum formula

Sn = (n (a1 + an)) / 2

S34 = (34(3 + 201))/2

s34 = (34(204)) / 2

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s34 = 3468 <=== the sum of the first 34 terms:

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3 years ago
How do you verify this trigonometric identity? cos^2 θcot^2 θ = cot^2 θ - cos^2 θ
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7nadin3 [17]

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Answer:

3(7x-5)

Step-by-step explanation:

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