Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
Answer:
a) 3x - 1
Step-by-step explanation:
f(x) + g(x)
(-2x + 6) + (5x - 7)
Drop the parentheses
-2x + 6 + 5x -7
5x and -2x can be combined as well as 6 and -7
So, 3x -1
Hello!
You could write this equation as seen below.
6+2(x+4)=0.5(3-x)
I hope this helps!
Answer:
y = −4x^2 + 4x − 3
Step-by-step explanation:
Answer: B. House mortgage
Step-by-step explanation: Anything tangible or intangible that can be sold or profitable is considered an asset. Hope it helps! xo