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MA_775_DIABLO [31]
3 years ago
6

If the gravitational force between objects of equal mass is 2.30 x 10^‐8 N when the objects are 10.0 m apart, what is the mass o

f each object?
Physics
1 answer:
Readme [11.4K]3 years ago
6 0

Answer:

Mass of each objects, m = 185.69 kg

Explanation:

The gravitational force between two equal masses is, F=2.3\times 10^{-8}\ N

Separation between the masses, d = 10 m

Let m is the mass of each object. The gravitational force is given by :

F=G\dfrac{m^2}{d^2}

m=\sqrt{\dfrac{F.d^2}{G}}

m=\sqrt{\dfrac{2.3\times 10^{-8}\times (10)^2}{6.67\times 10^{-11}}}

m = 185.69 kg

So, the mass of each objects is 185.69 kg. Hence, this is the required solution.

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QUESTION:

Will both buzzers sound in this circuit?

ANSWER:

No, Only first buzzer sound. It is because the 2nd buzzer doesn't connected.

6 0
3 years ago
During an experiment, you take a measurement of 18.3 inches. What is this measurement in centimeters? 1 in = 2.54 cm
Phoenix [80]
I Think The answer would be c I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you
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4 years ago
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When light waves travel, they _____.
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4 years ago
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a sample of ideal gas is originally at 40 degrees celsius. what is the final temperature of the gas if the volume is doubled and
Assoli18 [71]

Answer:

313 K or 40 degree celsius.

Explanation:

Initial , V_{i}=V_{0}

P_{i}=P_{0}

T_{i} =40+273=313K

Now, final

P_{f} =\frac{1}{2}P_{0}

V_{f} =2V_{0}

Combined  the ideal gas law

\frac{P_{i}V_{i}}{T_{i}}=\frac{P_{f}V_{f}}{T_{f}} \\\frac{P_{0}V_{0}}{T_{0}}=\frac{1}{2} \frac{P_{0}2V_{0}}{T_{f}} \\T_{f}=T_{0}\\T_{f}=313K

Therefore, the final temperature of ideal gas is 313 K.

4 0
4 years ago
Sam is observing the velocity of a car at different times. After three hours, the velocity of the car is 53 km/h. After six hour
Serhud [2]
For the answer to the question above, first find out the gradient. 

<span>m = rise/run </span>
<span>=(y2-y1)/(x2-x1) </span>

<span>the x's and y's are the points given: "After three hours, the velocity of the car is 53 km/h. After six hours, the velocity of the car is 62 km/h" </span>
<span>(x1,y1) = (3,53) </span>
<span>(x2,y2) = (6,62) </span>

<span>sub values back into the equation </span>
<span>m = (62-53)/(6-3) </span>
<span>m = 9/3 </span>
<span>m = 3 </span>

<span>now we use a point-slope form to find the the standard form </span>
<span>y-y1 = m(x-x1) </span>
<span>where x1 and y1 are any set of point given </span>
<span>y-53 = 3(x-3) </span>
<span>y-53 = 3x - 9 </span>
<span>y = 3x - 9 + 53 </span>
<span>y = 3x + 44 </span>

<span>y is the velocity of the car, x is the time.
</span>I hope this helps.
4 0
3 years ago
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