Which of these types of rock form near earths surface? Select all that apply.

Physics

2 answers:

OlgaM077 [116]3 years ago

8 0

A. Igneous

Extrusive igneous rocks cool and solidify quicker than intrusive igneous rocks. They are formed by the cooling of molten magma on the earth's surface.

Vanyuwa [196]3 years ago

5 0

Sedimentary (sed-uh-MEN-tuh-ree) rocks, unlike the other two kinds of rocks, are formed on or near Earth's surface. They form from sediments eroded from other rocks. The sediments may come from igneous, metamorphic, or other sedimentary rocks.

You might be interested in

True or False: Graphs provide a good visual representation of the relationships between the factors investigated in an experimen

Alecsey [184]

Answer:

True

Explanation:

Yes, the graph provides a good visual representation of the relationship between the factors being investigated when there are only two variables being studied at a time.
Sometimes a third variable is represented on a negative y-axis which plays a minor role in any one of the factors that may be conveniently represented.
Since we can draw only 2-dimensional diagrams on a paper, therefore, graphs are restricted to a couple of variables.
The independent variable is usually represented on the x-axis and the dependent variable is represented on the y-axis.
Graphs tell us the pattern of variation of a quantity with respect to another.

8 0

3 years ago

What causes waves to slow down: change in wave’s wavelength or change in its frequency and y?

Mashutka [201]

Answer:

Although the wave slows down, its frequency remains the same, due to the fact that its wavelength is shorter. When waves travel from one medium to another the frequency never changes.

3 0

3 years ago

A car leaves an intersection traveling west. Its position 4 sec later is 21 ft from the intersection. At the same time, another

Alex_Xolod [135]

Answer:

15.8 ft/s

Explanation:

$\frac{da}{dt}$ = Velocity of car A = 9 ft/s

a = Distance car A travels = 21 ft

$\frac{db}{dt}$ = Velocity of car B = 13 ft/s

b = Distance car B travels = ft

c = Distance between A and B after 4 seconds = √(a²+b²) = √(21²+28²) = √1225 ft

From Pythagoras theorem

a²+b² = c²

Now, differentiating with respect to time

$2a\frac{da}{dt}+2b\frac{db}{dt}=2c\frac{dc}{dt}\\\Rightarrow a\frac{da}{dt}+b\frac{db}{dt}=c\frac{dc}{dt}\\\Rightarrow \frac{dc}{dt}=\frac{a\frac{da}{dt}+b\frac{db}{dt}}{c}\\\Rightarrow \frac{dc}{dt}=\frac{21\times 9+28\times 13}{\sqrt{1225}}\\\Rightarrow \frac{dc}{dt}=15.8\ ft/s$