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neonofarm [45]
4 years ago
8

When x-rays of wavelength 0.312 nm are directed at a crystalline sample, the smallest bragg angle for a certain family of reflec

ting planes is found to be 28.5°. within the sample, the atoms lie on a simple cubic lattice, a 2-dimensional view of which is shown to the right. assuming that the constructive interference observed is due to the pair of diagonal planes indicated by the two dashed lines, find the distance a between neighboring atoms?
Physics
1 answer:
kozerog [31]4 years ago
8 0
The equation for bragg's law is nλ=2dsinθ. The smallest angle is when n=1 and we are told the angle is 28.5. d in our equation is the distance between atoms. So:

(1)(0.312*10^-9)=2dsin(28.5)

Solving for d we get

d=3.26925*10^-10m
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Read 2 more answers
The 5-lb collar is released from rest at A and travels along the frictionless guide. Determine the speed of the collar when it s
Sholpan [36]

Answer:

Explanation:

Stiffness of spring k equal to 4 lb/ft.

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Weight of the collar W is 15lb

Radius of curvature of curve guide is 1 feet

length of vertical rod is 1.5 feet

Initial speed of collar when released from rest at A is 0 feet per seconds  

use the energy conservation equation

 P_A +K_A=P_B+K_B

Estimate the potential energy , component as position B as below

P_A=Wh_1+\frac{1}{2} ks^2_1\\\\=5\times(1.5+1)+\frac{1}{2} \times 4 \times(1.5+1-0.5)^2\\\\=20.5lb.ft

Estimate the kinetic energy , component as position A as below

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Estimate the kinetic energy , component as position B as below

K_A=\frac{1}{2} \frac{W}{g} V^2_2\\\\=\frac{1}{2} \frac{5}{32.2} \times V^2_2\\\\=00777V^2_2

Substitute 20.5lb- ft for P_A

0.5lb-ft for P_B

0lb -ft for K_A

0.0777V_2^2 for K_B

20.5+0=0.5+0.777V^2_2\\\\V^2_2=257.6\\\\V_2=16.05

= 16.05ft/sec

7 0
3 years ago
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