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Rasek [7]
3 years ago
5

Choose yes or no to indicate whether the product is correct

Mathematics
1 answer:
serg [7]3 years ago
3 0
What is the product??
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A piece of land is 20cm by 5cm. A portion of the land by size 10cm by 2cm was used to cultivate tomatoes. what is the area of th
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80cm^2

Step-by-step explanation:

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Find the Dot Product if u=8i-7j and v=3i-4j?
Feliz [49]

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52

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u.v=(a1,b1).(a2,b2)

a1b1+a2b2

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(8)(3)+(-7)(−4)

24+28=52

4 0
3 years ago
Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2
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\bf ~~~~~~~~~~~~\textit{angle between two vectors }&#10;\\\\&#10;cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies &#10;\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\&#10;-------------------------------

\bf \begin{cases}&#10;v1=\ \textless \ -6,4\ \textgreater \ \\&#10;v2=\ \textless \ -3,6\ \textgreater \ \\&#10;------------\\&#10;v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\&#10;\qquad \qquad 42\\&#10;||v1||=\sqrt{(-6)^2+4^2}\\&#10;\qquad \sqrt{52}\\&#10;||v2||=\sqrt{(-3)^2+6^2}\\&#10;\qquad \sqrt{45}&#10;\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)&#10;\\\\\\&#10;\measuredangle \theta =cos^{-1}\left(  \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o
8 0
3 years ago
Help? Sorry if it’s pink
Vadim26 [7]
3 = 3/4(b - 8)
Switch sides
3/4(b - 8) = 3
Next, multiply both sides by 4
4 * 3/4(b - 8) = 3 * 4
Then simplify,
3(b - 8) = 12
Next, divide both sides by 3
3(b - 8)/3 = 12/3
Then, simplify
b - 8 = 4
Then, add 8 to both sides
b - 8 + 8 = 4 + 8
Simplify, b = 12
6 0
3 years ago
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