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Roman55 [17]
3 years ago
9

What is the value of x?

Mathematics
1 answer:
juin [17]3 years ago
8 0
Pythagoras says that x²+12²=13², so x=√(169-144)=√25=5
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When no net force is applied to a moving object, it still comes to rest because of its inertia.
mafiozo [28]

Answer:

A true

Step-by-step explanation:


3 0
4 years ago
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Which is the graph of the equation y-1=2/3(x-3)? <br> PLEASE ANSWER ASAP
alexgriva [62]

Answer:

Graph #1

Step-by-step explanation:

Compare your

y - 1 = (2/3)(x - 3) to

y - k = m(x - h).  We see that k = 1 and h = 3.

Thus, (1, 3) is a point on the graph.  This matches Graph #1.  

Note: Graph #1 and Graph #3 appear to be the same.  Why?

8 0
3 years ago
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Note that the right triangles with sides equal to 5, 12, 13 and 9, 12, 13 both have a side equal to 12. using this fact find the
kondor19780726 [428]
There is a mistake 9,12,13 is not a right triangle. but 9,12,15 is. IF you use this triangle instead, then the area of the 13,14,15 triangle is the sum of the area of the other two triangles.
6 0
4 years ago
Simplify the problem 2/sqrt 5
AURORKA [14]
2/sqrt 5

by rationalising the denominator,

2/sqrt 5 × sqrt 5/sqrt 5

= 2(sqrt 5)/sqrt 5(sqrt 5)

= 2 sqrt 5/5

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7 0
3 years ago
A ship at position (1, 0) on a nautical chart (with north in the positive y direction) sights a rock at position (6, 5). What is
OLga [1]

Answer:

The vector joining the ship to the rock is t= 7 i + 5 j

The direction is 0.9505 radians east of north.

Step-by-step explanation:

The position vector of the ship:

r= 1 i + 0 j

The position vector of the ship:

s= 6 i + 5 j

The vector joining the ship to the rock is:

t = r + s

t = (1 i + 0 j) + (6 i + 5 j)

t = 7 i + 5 j

The bearing of the rock to the ship is:

Θ= \frac{ \pi}{2} - arctan (\frac{5}{7})= 0.9505 radians

4 0
3 years ago
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