The graphs of f(x) and g(x) are transformed function from the function y = x^2
The set of inequalities do not have a solution
<h3>How to modify the graphs</h3>
From the graph, we have:
and 
To derive y < x^2 - 3, we simply change the equality sign in the function f(x) to less than.
To derive y > x^2 + 2, we perform the following transformation on the function g(x)
- Shift the function g(x) down by 2 units
- Reflect across the x-axis
- Shift the function g(x) down by 3 units
- Change the equality sign in the function g(x) to greater than
<h3>How to identify the solution set</h3>
The inequalities of the graphs become
y < x^2 - 3 and y > x^2 + 2
From the graph of the above inequalities (see attachment), we can see that the curves of the inequalities do not intersect.
Hence, the set of inequalities do not have a solution
Read more about inequalities at:
brainly.com/question/25275758
Answer:
The two sample t-test
Step-by-step explanation:
The appropriate test for thus is the two sample t test which is also known as the independent t test. This tests aims at determined whether there is a statistically significant difference between the means in two unrelated groups which in this context are a random sample with one type of preservative and another sample with another type of preservatives.
With this test, the researcher is able to compare the mean shelf lives of the bananas treated with the two different preservatives... The null hypothesis equalises the two means of the sample while the alternative does otherwise.
9514 1404 393
Answer:
34.5 square meters
Step-by-step explanation:
We assume you want to find the area of the shaded region. (The actual question is not visible here.)
The area of the triangle (including the rectangle) is given by the formula ...
A = 1/2bh
The figure shows the base of the triangle is 11 m, and the height is 1+5+3 = 9 m. So, the triangle area is ...
A = (1/2)(11 m)(9 m) = 49.5 m^2
The rectangle area is the product of its length and width:
A = LW
The figure shows the rectangle is 5 m high and 3 m wide, so its area is ...
A = (5 m)(3 m) = 15 m^2
The shaded area is the difference between the triangle area and the rectangle area:
shaded area = 49.5 m^2 - 15 m^2 = 34.5 m^2
The shaded region has an area of 34.5 square meters.
(4 hundred + 0 tens + 5 ones) + (1 ten) = 4 hundred + 1 ten + 5 ones
... = 415
The first thing you want to do is plug in x and y into both equations:
a(3) + b(4) = 4
b(3) + a(4) = 8
rearrange to line up a’s and b’s
3a + 4b = 4
4a + 3b = 8
now you want to choose a or b and multiply each equation by a number to make them have the same amount of a’s or b’s.
4(3a + 4b = 4) = 12a + 16b = 16
3(4a + 3b = 8) = 12a + 9b = 24
Now we subtract the bottom equation from the top and solve for b:
12a + 16b - (12a + 9b) = 16 - 24
7b = -8
b = -8/7
Now we plug back in for b to one of the original equations:
3a + 4(-8/7) = 4
3a + (-32/7) = 4
3a - (32/7) = 4
3a = 4 + (32/7)
3a = (28/7) + (32/7)
3a = 60/7
a = (60/7)/3 = 20/7.
Finally, plug a and b in together to double check using the second equation.
4a + 3b = 8
4(20/7) + 3(-8/7) = ?
(80/7) - (24/7) = ?
56/7 = 8.
