What is the area of this trapezoid?

A concrete patio is 5 2/3 feet wide. It has an area of 36 5/6 square feet. What is the length of the concrete patio

Aneli [31]

The length of the concrete patio is 6 1/2.
I got this answer by dividing 36 5/6 and 5 2/3. Therefore, answer is 6 1/2

4 0

2 years ago

Como resolver una fraccion heterogeneas de suma de 1/4 y 1/8

babunello [35]

I can’t understand because I speak English

6 0

3 years ago

Please help and explain why you got it right please

gtnhenbr [62]

Answer:

y+7 = -3 ( x-4)

Step-by-step explanation:

First find two points on the graph to find the slope

( 1,2) and ( 3,-4)

The slope is given by

m = ( y2-y1)/(x2-x1)

m = ( -4-2)/(3-1)

= -6/2

=-3

We can use the point slope form

y - y1 = m(x-x1) where m is the slope and x1,y1 is a point on the line

We have two choices with a slope of -3

We can either use and x coordinate of -2 or 4

for -2, the y coordinate is not shown

for 4 , the y coordinate is -7

Using ( 4, -7) and m = -3

y--7 = -3( x- 4)

y+7 = -3 ( x-4)

4 0

2 years ago

Read 2 more answers

Dylan Rieder is a statistics student investigating whether athletes have better balance than non-athletes for a thesis project.

Kobotan [32]

Answer:

$t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457$

$p_v =P(t_{75}$

Comparing the p value with a significance level for example $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.

Step-by-step explanation:

Data given and notation

$\bar X_{A}=3.7$ represent the mean for athletes

$\bar X_{NA}=4.1$ represent the mean for non athletes

$s_{A}=1.1$ represent the sample standard deviation for athletes

$s_{NA}=1.3$ represent the sample standard deviation for non athletes

$n_{A}=32$ sample size for the group 2

$n_{NA}=45$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the population mean for athletes is lower than the population mean for non athletes, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{NA}\geq 0$

Alternative hypothesis: $\mu_{A} - \mu_{NA}< 0$

We don't have the population standard deviation's, we can apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{A}-\bar X_{NA})-\Delta}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{NA}}{n_{NA}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457$

P value

We need to find first the degrees of freedom given by:

$df=n_A +n_{NA}-2=32+45-2=75$

Since is a one left tailed test the p value would be:

$p_v =P(t_{75}$

Comparing the p value with a significance level for example $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.

5 0

2 years ago

What is the solution (a, c) to this system of linear equations?

weeeeeb [17]

This is how you do it :) let me know if you have any questions. Hope this helps :)

4 0

3 years ago

Read 2 more answers