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sp2606 [1]
4 years ago
7

As a wave travels through water, the water particles travel in clockwise circles. The radius of these circles decreases as the d

epth as the depth into the water increases. An object floating on the water seems to bop up and down but it is also moving in a circle. The energy of the water wave travels
A) vertically
B) horizontally
C) in circle as well
D) with the water particles
Physics
2 answers:
natima [27]4 years ago
7 0
C because If it still moving in a circle it’s not going to change.
goldenfox [79]4 years ago
3 0

Answer:

b... horizontally

Explanation:

usatestprep babbbbeess

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Answer:

λ = 2.5m

Explanation:

Given the following :

Speed of sound (v) = 10m/s

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A rock is dropped from a 110-m-high cliff. How long does it take to fall (a) the first 55.0 m and (b) the second 55.0 m?
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Answer:

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We can solve this problem by dividing it into two parts, for the first 55 [m] and then the second part with the remaining 55 [m].

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v_{f}^{2}= v_{o}^{2}+2*g*y\\where:\\v_{o}=0\\g=gravity = 9.81[m/s^2]\\y=55 [m]\\v_{f}^{2}=0+2*9.81*55\\v_{f}=\sqrt{2*9.81*55} \\v_{f}=32.85[m/s]

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v_{f}=v_{o}+g*t\\t=\frac{v_{f}-v_{o}}{g}\\ t=\frac{32.85-0}{9.81}\\ t=3.35[s]

Now we can calculate the second time, but using as a initial velocity 32.85[m/s].

The final velocity will be:

v_{f}^{2}= v_{o}^{2}+2*g*y\\v_{f}=\sqrt{v_{o}^{2}+2*g*y} \\v_{f}=\sqrt{32.85^{2}+2*9.81*55 } \\v_{f}=46.45[m/s]

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