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sp2606 [1]
4 years ago
7

As a wave travels through water, the water particles travel in clockwise circles. The radius of these circles decreases as the d

epth as the depth into the water increases. An object floating on the water seems to bop up and down but it is also moving in a circle. The energy of the water wave travels
A) vertically
B) horizontally
C) in circle as well
D) with the water particles
Physics
2 answers:
natima [27]4 years ago
7 0
C because If it still moving in a circle it’s not going to change.
goldenfox [79]4 years ago
3 0

Answer:

b... horizontally

Explanation:

usatestprep babbbbeess

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During normal conditions, we only see the Sun’s __________, but during a solar eclipse, we get to see the _______________.
liberstina [14]
I would say A. because during the solar eclipse you cannot see the suns Photosphere at all, and the corona is the light that emits around the moon during the eclipse.
8 0
3 years ago
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if a person can jump 2m in earth surface how high can he jump in the moon (g of moon = 1.66m/s, g of earth = 9.8 m/s) [hint: use
julia-pushkina [17]

Answer:

h_{moon} = 11.8\ m

Explanation:

Since the work done is same everywhere in the universe. Hence, the work done in jumping will be same for the person on moon and earth:

W_{moon} = W_{earth}\\\\P.E_{moon} = P.E_{earth}\\\\mg_{moon}h_{moon} = mg_{earth}h_{earth}\\\\g_{moon}h_{moon} = g_{earth}h_{earth}\\\\(1.66\ m/s^2)h_{moon} = (9.8\ m/s^2)(2\ m)\\\\h_{moon} = \frac{(9.8\ m/s^2)(2\ m)}{1.66\ m/s^2}\\\\h_{moon} =  11.8\ m

5 0
3 years ago
A 18.6 V battery does 1,249.0 J of work transferring charge. How much charge is<br> transferred?
saw5 [17]

Answer: 67.2 C

Explanation:

Use formula

Voltage = work / charge

Charge = work / voltage

Charge = 1249 / 18.6 C

Charge = 67.2 C

3 0
3 years ago
True False Suppose I have a resistor of some resistance R. If I were to double the length and double the cross-sectional area of
skad [1K]

Explanation:

The resistance of a wire is given by :

R=\rho\dfrac{l}{A}

Where

\rho is the resistivity of the wire

l = initial length of the wire

A = initial area of cross section

If length and the area of cross section of the wire is doubled then new length is l' and A', l' = 2 l and A' = 2 A

So, new resistance of the wire is given by :

R'=\rho\dfrac{l'}{A'}

R'=\rho\dfrac{l}{A}

R' = R

So, the resistance of the wire remains the same on doubling the length and the area of wire.

4 0
3 years ago
Larger animals have sturdier bones than smaller animals. A mouse's skeleton is only a few percent of its body weight, compared t
Rama09 [41]

Answer:

a_s=4.8\times  10^{-2}~m^2

Explanation:

Given:

cross sectional area of the bone, a=4.8 \times 10^{-4} ~m^2

factor of up-scaling the dimensions, s=10

Since we need to find the upscaled area having two degrees of the dimension therefore the scaling factor gets squared for the area being it in 2-dimensions.

The scaled up area is:

a_s=a\times s^2

a_s=[4.8 \times 10^{-4}]\times 10^2

a_s=4.8\times  10^{-2}~m^2

7 0
3 years ago
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