<span>1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2</span>
Answer:
x ≤ 90?
Step-by-step explanation:
The line can be written in the form y=mx+b. Plugging -2 in for m , 1 in for x, and -3 in for y, we get -3=-2*1+b=-2+b. Adding 2 to both sides, we get b=-1 and our equation turns into y=-2x-1 since y and x stay variables. Plugging it into a graphing calculator, we get in (0,b) that b = -1
Slope is 2 and the y intercept is 4