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3 years ago

Multiply and simplify

Mathematics

1 answer:

emmasim [6.3K]3 years ago

8 0

Answer:

Step-by-step explanation:

It's easy:

$\frac{4}{16}* \frac{y^5}{y^2}$

$\frac{y^3}{4}$

So, the answer is B.

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How many solutions are there to the equation shown below? 7x + 12 = 5x – 8

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ArbitrLikvidat [17]

Testing the hypothesis in this problem which is a two-tailed test, we can conclude that there is not sufficient evidence to conclude that the mean time of installation has changed, since the p-value of the test is 0.0364 > 0.01,

At the null hypothesis, we test if the mean is of 25 minutes, that is:

$H_0: \mu = 25$

At the alternative hypothesis, we test if the mean has changed, that is, if it is different than 25 minutes.

$H_1: \mu \neq 25$

We have the standard deviation for the sample, thus, the t-distribution is used. The value of the test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which:

X is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

In this problem:

25 is tested at the null hypothesis, thus $\mu = 25$ .
Sample mean of 26.2 minutes, thus $X = 26.2$ .
Sample of 51, thus $n = 51$ .
Variance of 16, thus $s = \sqrt{16} = 4$ .

The value of the test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{26.2 - 25}{\frac{4}{\sqrt{51}}}$

$t = 2.14$

The p-value of the test is found using a two-tailed test(test if the mean is different of a value), with t = 2.14 and 50 degrees of freedom.

Using a t-distribution calculator, this p-value is of 0.0364.

Since the p-value of the test is 0.0364 > 0.01, there is not sufficient evidence to conclude that the mean time of installation has changed.

A similar problem is given at brainly.com/question/23777908

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