<span>4% is the same as 0.04 </span>
<span>so 0.04 x n = 56 where "n" is some number </span>
<span>0.04n = 56 Divide both sides by 0.04 </span>
<span>n = 1400</span>
Assuming the order required is as n-> inf.
As n->inf, o(log(n+1)) -> o(log(n)) since the 1 is insignificant compared with n.
We can similarly drop the "1" as n-> inf, the expression becomes log(n^2+1) ->
log(n^2)=2log(n) which is still o(log(n)).
So yes, both are o(log(n)).
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The answer is D, 4/3 x 3.14 x 2^3
Answer:
26^9
Step-by-step explanation:
