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Margarita [4]
3 years ago
5

Simplifying square roots problem below.

Mathematics
1 answer:
Mars2501 [29]3 years ago
6 0
Break x⁴ into x³ and x¹, watch the step below
\sqrt[3]{ x^{4} }
= \sqrt[3]{ x^{3+1} }

Remember that
\sqrt{ x^{m+n} } = \sqrt{ x^{m} }  \sqrt{ x^{n} }

Use the property above to simplify the root
= \sqrt[3]{ x^{3+1} }
=(\sqrt[3]{ x^{3} })( \sqrt[3]{x^{1}} )
= x ∛x

The answer is first option
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Step-by-step explanation:

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3 years ago
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Norma-Jean [14]
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So trying to get the variable alone...

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7 0
4 years ago
find the three consecutive odd integers such that the sum of twice the first and three times the second is 67 more than twice th
Elenna [48]

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Step-by-step explanation:

It can be convenient to work "consecutive integer" problems by using a variable to represent the middle one.

__

<h3>setup</h3>

Let x represent the middle integer. Then (x-2) is the first of the three odd integers, and (x+2) is the third. The given relation is ...

  2(x -2) +3x = 67 +2(x +2)

<h3>solution</h3>

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4 0
2 years ago
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