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Sav [38]
3 years ago
8

Helpppppp I don’t understand

Mathematics
1 answer:
8090 [49]3 years ago
6 0
Supplementary: Angles that add up to 180 degrees.
This means that angle 1 and angle 2 add up to 180 degrees. You can put them into an algebraic problem like I have in this (the image I have added), and solve for what x is. That is the key to finding out what angle 1 equals!
Once you have found x you can plug it into the equation you have for angles 1 and 2 to find if they equal 180.
Hope this helps!

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SIMPLE CONGRUENCE QUESTION!!! LOTS OF POINTS!
Monica [59]

Answer:

A. Side-Angle-Side (SAS).

Step-by-step explanation:

Sides go first. Side.

Angle next. Angle.

Side again. Side.

You got Side angle side.

7 0
2 years ago
How many factors does 72 have?<br> Eliminat<br> 14
aalyn [17]

Answer: <u>The factors of 72 are: 1,2,3,4,6,8,9,12,18,24,36,72. So basically 12, and if 72 doesn't count than it is 11.</u>

Step-by-step explanation: <em>Hope this helps.</em>

6 0
4 years ago
Read 2 more answers
Divide and make sure to reduce to LOWEST terms:
Ksju [112]
Just put it in the calculator and divide 4 by 5 then do 3 by 5 and keep on
3 0
2 years ago
Evaluate the following limit, if it exists : limx→0 (12xe^x−12x) / (cos(5x)−1)
Amanda [17]

Answer:

\lim_{x \to 0} \frac{12xe^x-12x}{cos(5x)-1}=-\frac{24}{25}

Step-by-step explanation:

Notice that \lim_{x \to 0} \frac{12xe^x-12x}{cos(5x)-1}=\frac{12(0)e^{0}-12(0)}{cos(5(0))-1}=\frac{0}{0}, which is in indeterminate form, so we must use L'Hôpital's rule which states that \lim_{x \to c} \frac{f(x)}{g(x)}=\lim_{x \to c} \frac{f'(x)}{g'(x)}. Basically, we keep differentiating the numerator and denominator until we can plug the limit in without having any discontinuities:

\frac{12xe^x-12x}{cos(5x)-1}\\\\\frac{12xe^x+12e^x-12}{-5sin(5x)}\\ \\\frac{12xe^x+12e^x+12e^x}{-25cos(5x)}

Now, plug in the limit and evaluate:

\frac{12(0)e^{0}+12e^{0}+12e^{0}}{-25cos(5(0))}\\ \\\frac{12+12}{-25cos(0)}\\ \\\frac{24}{-25}\\ \\-\frac{24}{25}

Thus, \lim_{x \to 0} \frac{12xe^x-12x}{cos(5x)-1}=-\frac{24}{25}

3 0
2 years ago
Determine the number of pounds of nuts selling for $6 per pound and raisins selling for $3 per pound
Luda [366]
For the mix you need 60 Ib of nuts and raisins, and 60 lb of mix will sell for $300.
Let <em>x</em> be the weight of nuts and <em>y</em> the weight of raisins needed for the mix.
Total weight = <em>x</em>+<em>y</em> = 60, so <em>y</em> = 60 - <em>x</em>
Total value = 6<em>x</em> + 3<em>y</em> = 300.  From the above, we can substitute the <em>y</em> for 60 - x:
Total value = 6<em>x</em> + 3(60 - <em>x</em>) = 300, which we can simplify to:
6<em>x</em> + 180 - 3<em>x</em> = 300, and simplify again to:
3<em>x</em> = 120, and again to:
<em>x</em> = 40.  We can now calculate<em> y</em> from the first equation y = 60 - <em>x</em>, so:
y = 20.
40 lb of nuts and 20 lb of raisins.  Check:
40 lb x $6/lb = $240, and 20 lb x $3/lb = $60, $240 + $60 = $300.



7 0
3 years ago
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