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sweet [91]
2 years ago
13

!!!!!!!I NEED HELP WITH THESE PROBLEMS. THANK YOU!!!!!

Mathematics
1 answer:
Viefleur [7K]2 years ago
6 0
The answer to your question is A

You might be interested in
you did 150 J of work lifting a 120 N backpack. how much did the backpack weigh in pounds?(hint:there are 4.448 N in one pound)
a_sh-v [17]

If the backpack weighs 120 N, then the equivalent
weight in pounds is about 26.98 .

All that business about lifting and joules of work is
completely irrelevant to this question.

3 0
3 years ago
g In a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained
Marat540 [252]

Answer:

95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

Step-by-step explanation:

We are given that in a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained a flu shot.

Firstly, the Pivotal quantity for 95% confidence interval for the population proportion is given by;

                          P.Q. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of residents 65-years or older who had obtained a flu shot = \frac{28}{111} = 0.25

          n = sample of residents 65-years or older = 111

          p = population proportion of residents who were getting the flu shot

<em>Here for constructing 95% confidence interval we have used One-sample z test for proportions.</em>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } },\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

   = [ 0.25-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } } , 0.25+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } } ]

   = [0.169 , 0.331]

Therefore, 95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

7 0
3 years ago
Help me with these 2 questions please
pishuonlain [190]

Answer:

I believe for the second one it's B, then for the third one it's D

Step-by-step explanation:

Oh also be careful w ur lunch # showing

4 0
2 years ago
How to work this out ?
Free_Kalibri [48]

Answer:

The solution is (-3, -2).

Step-by-step explanation:

Please note that if you simply add these 2 equations together, 9x - 9x = 0, and you are then left with -5y = 10.  Thus, y = -2.  Subbing -2 for y in the first equation, we get 9x - 8(-2) = -11, or 9x + 16 = -11.

Subtracting 16 from both sides, we get 9x = -27, so that x = -3.

The solution is (-3, -2).


6 0
2 years ago
How do you simplify this
Gala2k [10]
15 + 1 because you are using apsolute value so that negative 1 becomes a positive
8 0
3 years ago
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