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Nataly_w [17]
3 years ago
8

In recent years the mean number of miles driven per year by residents of a particular state was 11,568. A researcher wishes to t

est, at the 5% level of significance, whether the mean is different now. In a random sample of 62 drivers, the mean and sample standard deviation of the number of miles driven last year were 10,822 and 1,741, respectively.
(a) The relevant hypotheses are

(a) H0 :µ =11, 568 Vs Ha :µ ≠11, 568 (b) H0 :µ =10,822 Vs Ha :µ ≠10,822 (c) H0 : X =11, 568 Vs Ha : X ≠11, 568 (d) H0 : X =10,822 Vs Ha : X ≠10,822

(b) The value of the test statistic is about

(a) -3.345; (b) 3.376; (c) 3.345; (d) -2.855; (e) -3.376

(c) The rejection region is

(a) (-[infinity],-2]U[2,[infinity]) (b) (-[infinity],-2] (c) (-[infinity],-1.96]U[1.96,[infinity]) (d) (-[infinity],-1.96] (e) (-[infinity],-1.670]
Mathematics
2 answers:
svet-max [94.6K]3 years ago
7 0

Answer:

oksy

Step-by-step explanation:

disa [49]3 years ago
6 0

Answer:

516

Step-by-step explanation:

You should check the 561 with 6591

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Which number can each term of the equation be multiplied by to eliminate the fractions before solving?
scoray [572]

Answer: 12

Step-by-step explanation:

You can multiply by 12 because to get rid of the fractions all terms should be divided by the LCM (ie the smallest multiple that is exactly divisible by 2, 4 and 3)

Multiples of 3 = 3, 6, 9, 12

Multiples of 4 = 4, 8, 12, 16

Multiples of 2 = 2, 4, 6, 8, 10, 12

Therefore the fractions should be multiplied by 12

5 0
2 years ago
Read 2 more answers
10 points for this!!
MrMuchimi
This is the answer for your problem

7 0
2 years ago
The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of app
AfilCa [17]

Answer:

Q(t) = 4.5(1.013)^{t}

The world population at the beginning of 2019 will be of 7.45 billion people.

Step-by-step explanation:

The world population can be modeled by the following equation.

Q(t) = Q(0)(1+r)^{t}

In which Q(t) is the population in t years after 1980, in billions, Q(0) is the initial population and r is the growth rate.

The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of approximately 1.3%/year.

This means that Q(0) = 4.5, r = 0.013

So

Q(t) = Q(0)(1+r)^{t}

Q(t) = 4.5(1.013)^{t}

What will the world population be at the beginning of 2019 ?

2019 - 1980 = 39. So this is Q(39).

Q(t) = 4.5(1.013)^{t}

Q(39) = 4.5(1.013)^{39} = 7.45

The world population at the beginning of 2019 will be of 7.45 billion people.

6 0
3 years ago
An actor invests some money at 7%, and $48000 and more than twotimes the amount of 9%. The total annual interest earned from the
forsale [732]

Answer:

At 7% $54,000

At 9% $156,000

Step-by-step explanation:

Let x be the amount invested at 7%, Then 2x + 48000 will be the amount invested at 9%

We know that:

7% = 0.07 & 9% = 0.09

So we can write the interest equation as follows:

0.07x + 0.09 (2x + 48000) = 17820

0.07x + 0.18x + 4320 = 17820

0.25x + 4320 = 17820

Subtracting 4320 from both sides of the equation we get:

0.25x = 17820 - 4320

0.25x = 13500

Dividing both sides of the equation by 0.25 we get:

x = 13500 / 0.25

x = $54,000 invested at 7%

&

2 x 54000 + 48000

= $156,000 invested at 9%

Hence the amount invested at 7% is $54,000.

& the amount invested at 9% is $156,000.

5 0
3 years ago
A statue casts a shadow that is 45 feet
exis [7]
It’s not my answer but I think it’s correct!

6 0
3 years ago
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