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3 years ago

8

A telemarketer will make 25 calls in one hour. the probability of making a sale on any given call is .09. what is the probabilit

y that he will make at least one sale during the hour?

1 answer:

nignag [31]3 years ago

8 0

Oh really thats interesting

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A cylindrical glass is 40% full of liquid. If the base of the glass has a radius of 5 inches and the height of the glass

Elan Coil [88]

40

100

or the decimal 0.40. Notice that 80 out of 200 and 10 out of 25 are also 40%, since

80

200

=

10

25

=

40

100

5 0

2 years ago

Solve using elimination.<br> 8x – 6y = -6<br> 2x – 4y = -14

vovangra [49]

I’m not sure if you want the answer or how to do i’ll just give you both.
multiply the bottom by -4. then it should look like:
8x-6y=-6
-8x+16y=56
then cancel out the x’s and add/subtract the others, giving you: -2y=50. then divide 50 by -2 giving you: y=-25. then find x. plug in y to one of the equations. i usually do the one that hasn’t been messed with. 8x-6(25)=-6. then solve it like a normal two-step equation.
so the answer is: (18,-25)

7 0

3 years ago

The area of a square mat is 125 square inches. The best approximation of its length is inches. If the length of each side is inc

gtnhenbr [62]

The area of a square is simply the side length squared and we are given that the area is 125 so:

s^2=125

s=√125

s=5√5

Now using the area equation again, and adding 1 inch to s we have:

A=(s+1)^2, and using s found above we have:

A=(5√5+1)^2

A=125+10√5+1

A=126+10√5 in^2

A≈148.36 in^2 (to nearest hundredth of a square inch)

4 0

3 years ago

Read 2 more answers

In the xy-plane , the graph of y=x^2 and the circle with center ( 0,1) and the radius 3 have how many points of intersection ?

Nikitich [7]

There are 2 points of intersection

5 0

3 years ago

The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control a

Dafna11 [192]

Answer:

Probability that at least 490 do not result in birth defects = 0.1076

Step-by-step explanation:

Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.

To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects

Proof -

Given that,

P(birth that result in a birth defect) = 1/33

P(birth that not result in a birth defect) = 1 - 1/33 = 32/33

Now,

Given that, n = 500

X = Number of birth that does not result in birth defects

Now,

P(X ≥ 490) = $\sum\limits^{500}_{x=490} {^{500} C_{x} } (\frac{32}{33} )^{x} (\frac{1}{33} )^{500-x}$

= ${^{500} C_{490} } (\frac{32}{33} )^{490} (\frac{1}{33} )^{500-490}$ + .......+ ${^{500} C_{500} } (\frac{32}{33} )^{500} (\frac{1}{33} )^{500-500}$

= 0.04541 + ......+0.0000002079

= 0.1076

⇒Probability that at least 490 do not result in birth defects = 0.1076

4 0

3 years ago