Answer:
C=y=sin1/2x
Step-by-step explanation:
As given in the graph:
Amplitude= 1
period=2π
Finding function of sin that have period of 4π and amplitude 1
A: y=1/2sinx
Using the formula asin(bx-c)+d to find the amplitude and period
a=1/2
b=1
c=0
d=0
Amplitude=|a|
=1/2
Period= 2π/b
=2π
B: y=sin2x
Using the formula asin(bx-c)+d to find the amplitude and period
a=1
b=2
c=0
d=0
Amplitude=|a|
=1
Period= 2π/2
=π
C: y=sin1/2x
Using the formula asin(bx-c)+d to find the amplitude and period
a=1
b=1/2
c=0
d=0
Amplitude=|a|
=1
Period= 2π/1/2
=4π
D: y=sin1/4x
Using the formula asin(bx-c)+d to find the amplitude and period
a=1
b=1/4
c=0
d=0
Amplitude=|a|
=1
Period= 2π/1/4
=8π
Hence only c: y=sin1/2x has period of 2π and amplitude 1
*Answer* :
5.75
Explanation:
Let the unknown side = X
Cos() = adj/hyp
Cos(44)= X/8
X= 5.75
It's 5.
1/2 can also be written as 4/8.
So, it's 3 and 4/8 plus 1 and 4/8.
Answer:
43756
Step-by-step explanation:
Multiply
