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Gnesinka [82]
3 years ago
13

Triangle ABC is congruent to triangle XYZ. In ΔABC, AB = 12 cm and AC = 14 cm. In △XYZ, YZ = 10 cm and XZ = 14 cm. What is the p

erimeter of ΔABC? 36 cm 38 cm 40 cm 50 cm
Mathematics
1 answer:
daser333 [38]3 years ago
5 0

Answer: 36cm

Step-by-step explanation:

edge2020

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Which is the solution set of the inequality 15y-9<36?
AnnyKZ [126]

Answer:

The solution set is;

y < 3

This means the values of the real numbers set that are less than 3 in value

Step-by-step explanation:

Here, we want to get the solution set of the inequality

what we have to do is to get the value of y

We have this as;

15y < 36 + 9

15y < 45

y < 45/15

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3 0
3 years ago
Find the x-intercept and the y-intercept of the graph of the equation 1/3x + 9y = 15. Then graph the equation.
AleksAgata [21]

Answer: the x intercept is (45,0) and the y intercept is (0,5/3)

Step-by-step explanation:

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3 years ago
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Given:quadrillateral ABCD inscribed in a circle
son4ous [18]

Answer:

Step-by-step explanation:

Given: quadrilateral ABCD inscribed in a circle

To Prove:

1. ∠A and ∠C are supplementary.

2. ∠B and ∠D are supplementary.

Construction : Join AC and BD.

Proof: As, angle in same segment of circle are equal.Considering AB, BC, CD and DA as Segments, which are inside the circle,

∠1=∠2-----(1)

∠3=∠4-----(2)

∠5=∠6-------(3)

∠7=∠8------(4)

Also, sum of angles of quadrilateral is 360°.

⇒∠A+∠B+∠C+∠D=360°

→→∠1+∠2+∠3+∠4+∠5+∠6+∠7+∠8=360°→→→using 1,2,3,and 4

→→→2∠1+2∠4+2∠6+2∠8=360°

→→→→2( ∠1 +∠6) +2(∠4+∠8)=360°⇒Dividing both sides by 2,

→→→∠B + ∠D=180°as, ∠1 +∠6=∠B , ∠4+∠8=∠B------(A)

As, ∠A+∠B+∠C+∠D=360°

∠A+∠C+180°=360°

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∠A+∠C=180°

Hence proved.

credit: someone else

5 0
3 years ago
Let <img src="https://tex.z-dn.net/?f=%5Csf%20a%2Bb%2Ca-b%2Cab%2C%5Cdfrac%7Ba%7D%7Bb%7D" id="TexFormula1" title="\sf a+b,a-b,ab,
Black_prince [1.1K]

Answer:

  • 171/40 or 4 11/40

Step-by-step explanation:

<h3>AP given</h3>
  • a + b, a - b,  ab, a/b
<h3>To find</h3>
  • 6th term
<h3>Solution</h3>

Common difference

<u>Difference of first two</u>

  • d = (a -b) - (a + b) = -2b

<u>Difference of second two</u>

  • d= ab - (a - b)

<u>Difference of last two</u>

  • d = a/b - ab

<u>Now comparing d:</u>

  • -2b = ab - (a - b)
  • ab - a = - 3b
  • a(1 - b) = 3b
  • a = 3b/(1 - b)

and

  • a/b - ab = -2b
  • a(1/b - b) = -2b
  • a = 2b²/(b² - 1)

<u>Eliminating a:</u>

  • 2b²/(b² - 1) = 3b/(1 - b)
  • 2b/(b+1) = -3
  • 2b = -3b - 3
  • 5b = - 3
  • b = -3/5

<u>Finding a:</u>

  • a = 3b/(1 - b) =
  • 3*(-3/5) *1/(1 - (-3/5)) =
  • -9/5*5/8 =
  • -9/8

<u>So the first term is:</u>

  • a + b = -3/5 - 9/8 = -24/40 - 45/40 = - 69/40

<u>Common difference:</u>

  • d = -2b = -2(-3/5) = 6/5

<u>The 6th term:</u>

  • a₆ = a₁ + 5d =
  • -69/40 + 5*6/5 =
  • -69/40 + 240/40 =
  • 171/40 = 4 11/40
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3 years ago
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5+20 this answer answer

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3 years ago
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