Answer:
There can be 14,040,000 different passwords
Step-by-step explanation:
Number of permutations to order 3 letters and 2 numbers (total 5)
(AAANN, AANNA,AANAN,...)
= 5! / (3! 2!)
= 120 / (6*2)
= 10
For each permutation, the three distinct (English) letters can be arranged in
26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways
For each permutation, the two distinct digits can be arranged in
10!/(10-2)! = 10!/8! = 10*9 = 90 ways.
So the total number of distinct passwords is the product of all three permutations,
N = 10 * 15600 * 90 = 14,040,000
There is no number I can think of that would make the statement untrue.
The result of this when you subtract 83x from both sides leaves you with P = Q.
Unless you know differently, the equation says that P must equal Q no matter what x is. If there is such a condition, it is not obvious.
170 divided by 80 is 2.125, so 80 goes in 170, 2.125 times
Answer:
Step-by-step explanation:
A bag contains 4 blue, 5 white, and 6 green balls. ... There are 5 red and 15 black balls in a box, two are picked up at random
