Answer:
The vertex would be (-3, -1)
Step-by-step explanation:
Since this is in vertex form already, a(x-h)^2+k where h is the x value of the vetex, and k is y.
We would take the opposite of +3 and get -3, which gives us our x cordinate.
We don't change the k value, so it just stays -1, giving us our y value.
Therefore, the vertex is at (-3, -1)
Hope this helps!
Due to the symmetry of the paraboloid about the <em>z</em>-axis, you can treat this is a surface of revolution. Consider the curve
, with
, and revolve it about the <em>y</em>-axis. The area of the resulting surface is then

But perhaps you'd like the surface integral treatment. Parameterize the surface by

with
and
, where the third component follows from

Take the normal vector to the surface to be

The precise order of the partial derivatives doesn't matter, because we're ultimately interested in the magnitude of the cross product:

Then the area of the surface is

which reduces to the integral used in the surface-of-revolution setup.
No se si es la única forma que se yo te estoy diciendo en la clase y yo te llamo y te digo yo no
Answer:
y = - 2
Step-by-step explanation:
Locate x = 2 on the x- axis, go vertically down to meet the graph at (2, - 2 )
Then when x = 2, y = - 2
Answer:
<h3>C. Two vertical angles</h3>
This is your answer mate