I thinks it’s between A and B
Answer:

Step-by-step explanation:
Slant Height = 10 cm
Base Edge = 12 cm
<u>Finding the Height using Pythagorean Theorem:</u>
![\sf c^2 = a^2 + b^2 \\\\Where \ c = 10\ cm , b = 6\ cm [Half of 12] \ and \ a \ is \ height\\\\10^2 = a^2 + 6^2\\\\100=a^2 +36\\\\100-36 = a^2\\\\64 = a^2\\\\Taking \ sqrt \ on \ both \ sides\\\\Height= 8 \ cm](https://tex.z-dn.net/?f=%5Csf%20c%5E2%20%3D%20a%5E2%20%2B%20b%5E2%20%5C%5C%5C%5CWhere%20%5C%20c%20%3D%2010%5C%20cm%20%2C%20b%20%3D%206%5C%20cm%20%5BHalf%20of%2012%5D%20%5C%20and%20%5C%20a%20%5C%20is%20%5C%20height%5C%5C%5C%5C10%5E2%20%3D%20a%5E2%20%2B%206%5E2%5C%5C%5C%5C100%3Da%5E2%20%2B36%5C%5C%5C%5C100-36%20%3D%20a%5E2%5C%5C%5C%5C64%20%3D%20a%5E2%5C%5C%5C%5CTaking%20%5C%20sqrt%20%5C%20on%20%5C%20both%20%5C%20sides%5C%5C%5C%5CHeight%3D%208%20%5C%20cm)
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
<u>Now, Finding the volume:</u>

![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h2>~AnonymousHelper1807</h2>
The answer is 240
Explanation: The Least Common Multiple (LCM) is the smallest number that two or more numbers will divide into evenly. NOTE: to find LCM you first need to know how to find GCD.
First we will find LCM for first two numbers ( 16 and24 ).
Step 1: Find the GCD (Greatest Common Divisor ) of 16 and 24 which is 8.
Step 2: Multiply the numbers 16 and 24 together ( 16 * 24 = 384 )
Step 3: Divide the 384 with 8. (384/8 = 48)
So, the LCM of 16 and 24 is 48.
Now we will find the LCM of above result (48) and third number ( 40 ) using the same procedure.
The result of this part is 240
Answer: Try using calculatorsoup dot com, you need to be more specific, and use Find A, C and r | Given d?
radius r = 7.5 in
diameter d = 15 in
circumference C = 47.123889803847 in
area A = 176.71458676443 in2
In Terms of Pi π
circumference C = 15 π in
area A = 56.25 π in2
Step-by-step explanation:
<span><span> STEP 1. </span><span><span>x/5+6= 36
STEP 2. x/5 = 30
STEP TRES x= 150</span> </span></span>