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3 years ago

Do Earth’s oceans gain or lose water, considering evaporation and precipitation together? How much?

1 answer:

7 0

Much of the precipitation in large bodies of water occurs at the surface. The ocean loses about 37000 km cubed considering evaporation and precipitation.

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HELPPPPPPPPPPPPPPPPPPPPPPPPPP

aev [14]

Answer:

Explanation:

through the desk....here desk is the student's medium to hear the sound. its oblivious because when he lifts his head away from the desk he hears nothing else

6 0

2 years ago

A ball rolls downhill with a constant acceleration of 4m/s squared. If it started from rest,it’s velocity at the end of 3 meters

vladimir2022 [97]

Answer:

4.9 m/s

Explanation:

Since the motion of the ball is a uniformly accelerated motion (constant acceleration), we can solve the problem by using the following suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the ball in this problem,

u = 0 (it starts from rest)

$a=4 m/s^2$ is the acceleration

s = 3 m is the distance covered

Solving for v,

$v=\sqrt{u^2+2as}=\sqrt{0+2(4)(3)}=4.9 m/s$

3 0

3 years ago

Is there a frame of reference one can go into that seems to eliminate gravity as Newton described it?

andriy [413]

Answer:

Yes such a frame exists: a free-fall (free-float frame) frame. This frame of reference is subject only to gravity and no forces such as electromagnetic forces or nuclear forces.

3 0

3 years ago

A 2190 kg car moving east at 10.5 m/s collides with a 3220 kg car moving east. The cars stick together and move east as a unit a

Bezzdna [24]

To solve this problem it is necessary to apply the concepts related to the conservation of the Momentum describing the inelastic collision of two bodies. By definition the collision between the two bodies is given as:

$m_1v_1+m_2v_2 = (m_1+m_2)V_f$

Where,

$m_{1,2}$ = Mass of each object

$v_{1,2}$ = Initial Velocity of Each object

$V_f$ = Final Velocity

Our values are given as

$m_1 = 2190Kg$

$v_1 =10.5m/s$

$m_2 = 3220kg$

$V_f = 4.74m/s$

Replacing we have that

$m_1v_1+m_2v_2 = (m_1+m_2)V_f$

$(2190)(10.5)+(3220)v_2 = (2190+3220)(4.74)$

$v_2 = 0.8224m/s$

Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s

8 0

3 years ago

List and describe three biological applications of electricity

mihalych1998 [28]

Before we dive into how electricity is used around the home it is worth putting household electricity use in perspective.

Household electricity use generally makes up about a third of total electricity consumption in most developed nations. Using data from the European Union we can give an example of how electricity demand is split among different sectors.

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Read more at http://shrinkthatfootprint.com/how-do-we-use-electricity#DfE5FuAPpy6Z5TBH.99

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7 0

2 years ago