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3 years ago

On a hot day, warm air on land rises and collides with cool air. Which of these weather conditions is most likely to follow?

Physics

2 answers:

stepan [7]3 years ago

5 0

Answer:

D. thunderstorm

Explanation:

If it is a warm day and the cool air collides with the warm air that comes from land, the most probable to happen would be a thunderstorm, since the cool air is more dense than warm air, the warm air would go up and condense water this will cause for a thunderstorm.

Sliva [168]3 years ago

3 0

I think its......C. Hurricane

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Sasha sits on a horse on a carousel 3.5 m from the center of the circle. She makes a revolution once every 8.2 seconds. What is

Leokris [45]

Answer: 2.7 m/s

Explanation:

Given the following :

Period (T) = 8.2 seconds

Radius = 3.5 m

The tangential speed is given as:

V = Radius × ω

ω = angular speed = (2 × pi) / T

ω = (2 × 22/7) / 8.2

ω = 6.2857142 / 8.2

ω = 0.7665505

Therefore, tangential speed (V) equals;

r × ω

3.5 × 0.7665505 = 2.6829268 m/s

2.7 m/s

6 0

4 years ago

What is density?

a_sh-v [17]

Answer:

B- The amount of matter in a certain

amount of space

Explanation:

Density is the amount of matter an object has in a certain space. To find density, divide the mass of an object by the volume of an object.

8 0

3 years ago

Read 2 more answers

A car drives 23m/s east for 35 seconds. What is the displacement?

Lina20 [59]

Answer:

805m

Explanation:

Speed = displacement/time

Speed = 23m/s

Time = 35s

Displacement = speed × time

= 23 × 35

= 805m

5 0

3 years ago

In this type of polarization a Polaroid filter serves as a device that filters out one-half of the vibrations.

erik [133]

The answer is d.
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6 0

3 years ago

It is measured that 3/4 of a body's volume is submerged in oil of density 800kg/m³

Evgesh-ka [11]

Complete question:

It is measured that 3/4 of a body's volume is submerged in oil of density 800kg/m³. What is the specific gravity of oil?

Answer:

The specific gravity of the oil is 0.8.

Explanation:

Given;

density of the oil, $\rho_o$ = 800 kg/m³

density of water, $\rho_w$ = 1000 kg/m³

The specific gravity of any substance is the ratio of the substance density to the density of water.

Specific gravity of the oil = density of the oil / density of water

Specific gravity of the oil = 800/1000

Specific gravity of the oil = 0.8

Therefore, the specific gravity of the oil is 0.8.

8 0

3 years ago