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MAXImum [283]
3 years ago
10

A 10 kg mass car initially at rest on a horizontal track is pushed by a horizontal force of 10 N magnitude. If we neglect the fr

iction force between the car and the track, calculate how much the car travels in 10 s
Physics
1 answer:
vlada-n [284]3 years ago
5 0

Answer:

50 m

Explanation:

F = ma

10 N = (10 kg) a

a = 1 m/s²

Given:

v₀ = 0 m/s

a = 1 m/s²

t = 10 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (10 s) + ½ (1 m/s²) (10 s)²

Δx = 50 m

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Answer:

a

Explanation:

the plane is not going up and the rest are true

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3 years ago
When growing tomatoes with little sunlight, will using a mirror to reflect the sunlight give the same result as direct sunlight?
telo118 [61]

Answer:

No, it is not d true light

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4 0
4 years ago
The graph below represents the relationship between the force exerted on an elevator and the distance the elevator is lifted.
Stella [2.4K]

I have three problems with this question.

#1). If you copied the question exactly the way it's written,
then the question is written very badly.  The wording is
misleading, and the more you try to think about it and
puzzle it out, the more it'll damage your understanding
of Physics.

There is no relationship between the force exerted on an
elevator and the distance the elevator is lifted.

-- If the force is anything more than the weight of the elevator ...
even one ounce more ... then it'll lift the elevator as high as
you want. 

-- If the force is anything less than the weight of the elevator ...
even one ounce less, then that elevator is headed for the bottom.

#2).  You didn't post any graph below, so if we need the graph
to answer the question, then we can't answer the question.

#3).  I guess that's OK, because you didn't ask any question.  
8 0
3 years ago
A frictionless piston-cylinder device contains 4.5 kg of nitrogen at 110 kPa and 200 K. Nitrogen is now compressed slowly accord
pochemuha

Answer:

427.392 kJ

Explanation:

m = Mass of gas = 4.5 kg

Initial temperature = 200 K

Final temperature = 360 K

R = Mass specific gas constant = 296.8 J/kgK

\gamma = Specific heat ratio = 1.5

Work done for a polytropic process is given by

W=\frac{mR\Delta T}{1-\gamma}\\\Rightarrow W=\frac{4.5\times 296.8(360-200)}{1-1.5}\\\Rightarrow W=-427392\ J\\\Rightarrow W=-427.392\ kJ

The work input during the process is -427.392 kJ

3 0
3 years ago
How many centimeters are in 3.50 feet?
Kazeer [188]
106.68 centimetres are in 3.50 feet
4 0
3 years ago
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