Answer:
the rate of flow of electric charge past a point or region. An electric current is said to exist when there is a net flow of electric charge through a region. In electric circuits this charge is often carried by electrons moving through a wire. Aug 29 2019
Explanation:
Answer:
We will be effected not only with health, but also with our ability to carry out our genes to the next generation.
Explanation:
Our health is important, as we all know, so anything that happens to the digestive system will have a serious problem to our longevity, our reproductive system is also important to carry out our genes, and give birth to a new generation, it wouldn't effect us if only 1 person couldnt reproduce, but if everyone had a problem in their reproductive system, it would mean the extinction of all humanity.
Thermal energy is transferred by when objects touch.
3. Conduction ✔
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- The heat transfer that occurs between two objects when they touch each other is called .
- Heat is always transferred from the object at the higher temperature to the object with the lower temperature.
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Answer:
a) Q1= Q2= 11.75×10^-6Coulombs
b) Q1 =15×10^-6coulombs
Q2 = 38.75×10^-6coulombs
Explanation:
a) For a series connected capacitors C1 and C2, their equivalent capacitance C is expressed as
1/Ct = 1/C1 + 1/C2
Given C1 = 3.00 μF C2 = 7.75μF
1/Ct = 1/3+1/7.73
1/Ct = 0.333+ 0.129
1/Ct = 0.462
Ct = 1/0.462
Ct = 2.35μF
V = 5.00Volts
To calculate the charge on each each capacitors, we use the formula Q = CtV where Cf is the total equivalent capacitance
Q = 2.35×10^-6× 5
Q = 11.75×10^-6Coulombs
Since same charge flows through a series connected capacitors, therefore Q1= Q2=
11.75×10^-6Coulombs
b) If the capacitors are connected in parallel, their equivalent capacitance will be C = C1+C2
C = 3.00 μF + 7.75 μF
C = 10.75 μF
For 3.00 μF capacitance, the charge on it will be Q1 = C1V
Q1 = 3×10^-6 × 5
Q1 =15×10^-6coulombs
For 7.75 μF capacitance, the charge on it will be Q2 = 7.75×10^-6×5
Q2 = 38.75×10^-6coulombs
Note that for a parallel connected capacitors, same voltage flows through them but different charge, hence the need to use the same value of the voltage for both capacitors.
Answer: 2.73m/s
Explanation:
Potential energy of the water is turned into kinetic energy
mgd = mv^2/2
Where m = mass of water
g = acceleration due to gravity = 9.81m/s^2
d = depth of the water = 0.38m
v = velocity of leaking water
m × 9.81 × 0.38 = mv^2/
eliminate m on both sides and multiply through by 2
7.4456 = v^2
v = sqrt(7.4456)
v = 2.73m/s