3 years ago

A 12.3 n force is applied to a 3.65 kg object. Determine the acceleration of the object

Physics

1 answer:

trasher [3.6K]3 years ago

5 0

Umm what grade are you in ?

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Explanation:

Given that,

Heat required, Q = 1200 J

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$Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{1200}{20\times 6}\\\\c=10\ J/kg^{\circ} C$

So, the specific heat of the object is $10\ J/kg^{\circ} C$ .

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3 years ago

A 12.3 n force is applied to a 3.65 kg object. Determine the acceleration of the object​

A 12.3 n force is applied to a 3.65 kg object. Determine the acceleration of the object