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3 years ago

X =A.1B.3C.7Picture Provided Below

Mathematics

1 answer:

Yakvenalex [24]3 years ago

7 0

Answer:

B 3

Step-by-step explanation:

We can use the secant-secant formula:

(whole secant) x (external part) = (whole secant) x (external part)

9 * 4 = 12 *x

36 = 12x

Divide each side by 12

36/12 =12x/12

3 =x

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Two integers, a and b have product of -48 what is the greatest possible sum of a and b.

dusya [7]

The factors of 48 are:
1 x 48
2 x 24
3 x 16
4 x 12
6 x 8
and visa versa: 48 x 1 etc.

To make the product negative, one of the factors has to be positive and one has to be negative. To find the greatest sum, make the bigger number the positive factor and the smaller number the negative factor. So, -1 x 48 = -48 and the sum of -1 + 48 = 47 which would be the greatest possible sum.

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4 years ago

Pls help for geometry

Alex787 [66]

Answer:20

Step-by-step explana

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3 years ago

At a 20th high school reunion, all the classmates were asked the number of children they had. The probability of having a partic

finlep [7]

Answer:

a) We need to check two conditions:

1) $\sum_{i=1}^n P_i = 1$

$0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1$

2) $P_i \geq 0 , \forall i=1,2,...,n$

So we satisfy the two conditions so then we have a probability distribution

b) $P(C \geq 1)$

And we can use the complement rule and we got:

$P(C \geq 1)= 1-P(C$

c) $P(C=0) = 0.05$

d) For this case we see that the result from part b use the probability calculated from part c using the complement rule.

Step-by-step explanation:

For this case we have the following probability distribution given:

C 0 1 2 3 4 5 6 7 8

P 0.05 0.14 0.34 0.24 0.11 0.07 0.02 0.02 0.01

And we assume the following questions:

a) Verify that this is a probability distribution

We need to check two conditions:

1) $\sum_{i=1}^n P_i = 1$

$0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1$

2) $P_i \geq 0 , \forall i=1,2,...,n$

So we satisfy the two conditions so then we have a probability distribution

b) What is the probability one randonmly chosen classmate has at least one child

For this case we want this probability:

$P(C \geq 1)$

And we can use the complement rule and we got:

$P(C \geq 1)= 1-P(C$

c) What is the probability one randonmly chosen classmate has no children

For this case we want this probability:

$P(C=0) = 0.05$

d) Look at the answers for parts b and c and explain their relationship

For this case we see that the result from part b use the probability calculated from part c using the complement rule.

5 0

3 years ago

A taxi driver had 27 fares to and from the airport last Monday. The price for a ride to the airport is $14, and the price for a

OLga [1]

Answer:

(15, 12)

Step-by-step explanation:

Let's generate two systems of equations that fit this scenario.

Number of trips to the airport = x

Number of trips from the airport = y

Total number of trips to and from the airport = 27

Thus:

$x + y = 27$ => equation 1.

Total price for trips to the Airport = 14*x = 14x

Total price of trips from the airport = 7*y = 7y

Total collected for the day = $294

Thus:

$14x + 7y = 294$ => equation 2.

Multiply equation 1 by 7, and multiply equation 2 by 1 to make both equations equivalent.

7 × $x + y = 27$

1 × $14x + 7y = 294$

Thus:

$7x + 7y = 189$ => equation 3

$14x + 7y = 294$ => equation 4

Subtract equation 4 from equation 3

-7x = -105

Divide both sides by -7

x = 15

Substitute x = 15 in equation 1

$x + y = 27$

$15 + y = 27$

Subtract both sides by 15

$y = 27 - 15$

$y = 12$

The ordered pair would be (15, 12)

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3 years ago

Geometry...Please help as soon as possible please and Thank you!!!

Kaylis [27]

Answer:

I answered the question according to "ASA" Angle, side, angle

.....

Step-by-step explanation:

Note : I'm not a teacher but I'm quite sure about my answer...

Anyway...

If I'm wrong just tell me...

.....

GOOD LUCK... ❤️

4 0

3 years ago