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katovenus [111]
3 years ago
5

A reckless coyote engineer straps on a pair of ice skates and attaches a rocket capable of producing 5.0 × 10 3 N of thrust to h

is back. Together, the coyote and the rocket have a mass of 120 kg. If the coyote starts at rest on level, frictionless ice and bends over such that the rocket thrust is directed parallel to the ice, what is his final speed if the rocket burns for 5.0 s?
Physics
1 answer:
Marianna [84]3 years ago
3 0

Answer:

208.33 m/s

Explanation:

t = Time taken

u = Initial velocity = 0

v = Final velocity

a = Acceleration

m = Mass of coyote and the rocket = 120 kg

F = Force of thrust produced by the rockets = 5\times 10^3\ N

F=ma\\\Rightarrow a=\frac{F}{m}\\\Rightarrow a=\frac{5\times 10^3}{120}\\\Rightarrow a=\frac{125}{3}\ m/s^2

v=u+at\\\Rightarrow v=0+\frac{125}{3}\times 5\\\Rightarrow v=208.33\ m/s

Velocity of the rocket at 5 seconds is 208.33 m/s

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Minimum work = 5060 J

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Final speed of the bucket (v) = 4.0 m/s

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