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3 years ago

Carly rode her bike for 300 meters in 30 seconds. One can calculate her

Physics

1 answer:

Nutka1998 [239]3 years ago

5 0

Answer:

Explanation:

300 ÷ 30 = 10

Answer - 10

Hope this helps!!!

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In a very busy off-campus eatery one chef sends a 201 g broccoli-tomato-pickle-onion-mushroom pizza sliding down the counter fro

Murrr4er [49]

Answer:

The correct answer is:

(A) to the left

(B) at speed -0.8725 m/s

Explanation:

The given values are:

Plate 1:

Mass,

m₁ = 201 g

Velocity,

v₁ = +1.79 m/s

Plate 2:

Mass,

m₁ = 335 g

Velocity,

v₁ = -2.47 m/s

According to the conservation of momentum, we get

⇒ $m_1v_1+m_2v_2=(m_1+m_2)v$

then,

⇒ $v=\frac{m_1v_1+m_2v_2}{m_1+m_2}$

On substituting the values, we get

⇒ $=\frac{201\times 1.79+335\times (-2.47)}{201+335}$

⇒ $=\frac{359.79-827.45}{536}$

⇒ $=\frac{-467.66}{536}$

⇒ $=-0.8725$ (to the left)

3 0

2 years ago

A mass 25kg is attached to a spring which is held stretched a distance 120 cm by a force F=300N (Fig. 7-28), and then released.

azamat

Explanation:

Spring is stretched by force f to distance

"X"

now here by force balance we can say

f = kx

k = !

now here we will we say that energy stored in the spring will convert into kinetic energy

kx² = mv²

(x² = mv²

now solving above equation we will have

PART 2)

now for half of the extension again we can use energy conservation

ka²-k(x/2)² = 1 {mv²

¾fx=mv²

now the speed is given as

3 fr 4m V=

4 0

2 years ago

Help me someone ?...

Burka [1]

Gradpoint? The answer is B

8 0

3 years ago

Will a planet or comet be moving faster in its orbit when it is farther from or closer to the sun?

anastassius [24]

No difference.

A planet, asteroid, space station, rock, empty fuel tank, asteroid,
lost space probe, TV satellite, orbiting telescope, moon, or comet,
if they're traveling in the same orbit around the same central body,
all have the same speed at the same point in the orbit.

5 0

3 years ago

Light of wavelength 478 nm in air falls on two slits 6.53 mm apart. The slits are immersed in water, as is a viewing screen 30.8

cluponka [151]

The distance between the two fringes is 0.0225 mm.

<u>Explanation:</u>

As per Young's double slit experiment, the distance between the fringes can be observed for the bright constructive interference fringes. So if we know the distance between the separation of slits. the distance of the mirror placed away from the slit, then the distance between two fringes can be observed using the below formula.

$y=\frac{m\times wavelength\times D}{d}$

Here y is the distance between the fringes on screen, D is the distance of the screen from the slits and d is the distance between the slits. Also m is the order of the interference which is generally considered as 1.

So, in the present case, D = 30.8 cm = 0.308 m, d = 6.53×10⁻³ m, wavelength = 478 nm and m = 1.

So, $y = \frac{1\times 478\times 10^{-9} \times 0.308}{6.53\times 10^{-3} }$

$y =22.546\times 10^{-9+3}=22.546\times 10^{-6} m=0.0225\ mm.$

So, the distance between the two fringes is 0.0225 mm.

6 0

3 years ago

Carly rode her bike for 300 meters in 30 seconds. One can calculate her​

Carly rode her bike for 300 meters in 30 seconds. One can calculate her