Answer:
Explanation:
Let the radius of track required be r.
Centripetal force will be provided by frictional force which will be equal to
m v²/ r
Frictional force = mg x μ
So
m v² /r = mg μ
r = v² / μ g =
v = 29 km /h = 8.05 m /s
r =( 8.05 x 8.05 ) /( .32 x 9.8 ) = 20.66 m
The number of cycles of a periodic wave per unit time is called the wave's "frequency". The height at which the peaks of the waves reside is the "amplitude".
Answer:
Therefore,
The magnitude of the force per unit length that one wire exerts on the other is

Explanation:
Given:
Two long, parallel wires separated by a distance,
d = 3.50 cm = 0.035 meter
Currents,

To Find:
Magnitude of the force per unit length that one wire exerts on the other,

Solution:
Magnitude of the force per unit length on each of @ parallel wires seperated by the distance d and carrying currents I₁ and I₂ is given by,

where,

Substituting the values we get


Therefore,
The magnitude of the force per unit length that one wire exerts on the other is

It would be D) the rope is pulled to the right. This is because their is a greater force in that direction.